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2 years ago

Find the distance between points P(7,7) and Q(1,2) to the nearest tenth

Mathematics

1 answer:

ad-work [718]2 years ago

3 0

Answer:

7.8 units

Step-by-step explanation:

P(Xp, Yp)= (7,7)

Q(Xq, Yq)= (1,2)

distance= l= $\sqrt{(Xp-Xq)^{2} +(Yp-Yq)^{2}}$

l= $\sqrt{(7-1)^{2} +(7-2)^{2}}$

l= $\sqrt{6^{2} } +5^{2}$

l= $\sqrt{61}$

l=7.8102 (to 4 dec. places)

I= 7.8 (to nearest tenth)

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-(1+7x)=6(-7-x)+36 <br> Alg 2

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Let's solve your equation step-by-step.

−(1+7x)=6(−7−x)+36

Step 1: Simplify both sides of the equation.

−(1+7x)=6(−7−x)+36

−7x+−1=(6)(−7)+(6)(−x)+36(Distribute)

−7x+−1=−42+−6x+36

−7x−1=(−6x)+(−42+36)(Combine Like Terms)

−7x−1=−6x+−6

−7x−1=−6x−6

Step 2: Add 6x to both sides.

−7x−1+6x=−6x−6+6x

−x−1=−6

Step 3: Add 1 to both sides.

−x−1+1=−6+1

−x=−5

Step 4: Divide both sides by -1.

−x

−1

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x=5

Answer:

x=5

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Suppose ABC is a right triangle with sides a, b, and c and right angle at C. Find the unknown side length using the Pythagorean

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Answer:

a = $\sqrt{7}$

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.:

<em>Suppose ABC is a right triangle with sides a, b, and c and right angle at C. Find the unknown side length using the Pythagorean theorem and then find the values of the six trigonometric functions for angle B. when b=3 and c=4</em>.

My answer:

We will Pythagoras theorem, which states that the sum of squares of two legs of a right triangle is equal to the square of the hypotenuse of right triangle. Because the question says that ABC is a right triangle.

$a^2+b^2=c^2$

Given that: b=3 and c=4

$a^2+3^2=4^2a^2+9=16a^2+9-9=16-9a^2=7$

so a = $\sqrt{7}$

We know that tangent relates opposite side of a right triangle with adjacent side.

$\text{tan}(B)=\frac{a}{b}\\\text{tan}(B)=\frac{\sqrt{7}}{3}$

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Find the distance between points P(7,7) and Q(1,2) to the nearest tenth​

Find the distance between points P(7,7) and Q(1,2) to the nearest tenth