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3 years ago

Find the distance between points P(7,7) and Q(1,2) to the nearest tenth

Mathematics

1 answer:

ad-work [718]3 years ago

3 0

Answer:

7.8 units

Step-by-step explanation:

P(Xp, Yp)= (7,7)

Q(Xq, Yq)= (1,2)

distance= l= $\sqrt{(Xp-Xq)^{2} +(Yp-Yq)^{2}}$

l= $\sqrt{(7-1)^{2} +(7-2)^{2}}$

l= $\sqrt{6^{2} } +5^{2}$

l= $\sqrt{61}$

l=7.8102 (to 4 dec. places)

I= 7.8 (to nearest tenth)

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(c)

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Step-by-step explanation:

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$P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168$

Solving (c): $\lim_{t \to \infty} P(t)$

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of $e^{-ct}$ decreases

This implies that:

${t \to \infty} = {e^{-ct} \to 0}$

So:

The value of P(t) for large values is:

$P(\infty) = \frac{1200}{1 + 11 * 0}$

$P(\infty) = \frac{1200}{1 + 0}$

$P(\infty) = \frac{1200}{1}$

$P(\infty) = 1200$

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3 years ago

Find the distance between points P(7,7) and Q(1,2) to the nearest tenth​

Find the distance between points P(7,7) and Q(1,2) to the nearest tenth