Question

Find the distance between points P(7,7) and Q(1,2) to the nearest tenth​

Answer 1

Answer:

7.8 units

Step-by-step explanation:

P(Xp, Yp)= (7,7)

Q(Xq, Yq)= (1,2)

distance= l=$\sqrt{(Xp-Xq)^{2} +(Yp-Yq)^{2}}$

l=$\sqrt{(7-1)^{2} +(7-2)^{2}}$

l= $\sqrt{6^{2} } +5^{2}$

l=$\sqrt{61}$

l=7.8102 (to 4 dec. places)

I= 7.8 (to nearest tenth)