3 years ago

Find the distance between points P(7,7) and Q(1,2) to the nearest tenth

Mathematics

1 answer:

ad-work [718]3 years ago

3 0

Answer:

7.8 units

Step-by-step explanation:

P(Xp, Yp)= (7,7)

Q(Xq, Yq)= (1,2)

distance= l= $\sqrt{(Xp-Xq)^{2} +(Yp-Yq)^{2}}$

l= $\sqrt{(7-1)^{2} +(7-2)^{2}}$

l= $\sqrt{6^{2} } +5^{2}$

l= $\sqrt{61}$

l=7.8102 (to 4 dec. places)

I= 7.8 (to nearest tenth)

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Find the distance between points P(7,7) and Q(1,2) to the nearest tenth​

Find the distance between points P(7,7) and Q(1,2) to the nearest tenth