Answer:
Step-by-step explanation:
This is already factored for us, which is really nice, so now all we need to do is apply the Zero Product Property to the sets of parenthesis and solve for x, which will give us the 2 times that the object is on the ground.
x + 1 = 0 so
x = -1
x - 9 = 0 so
x = 9
We all know that time cannot ever be negative, so the time that the object is on the ground is 9 seconds after it's launched (which was from an initial height of 45 meters).
<span>2.5 – 1.2x < 6.5 – 3.2x
-1.2x + 3.2x < 6.5 - 2.5
3.2x - 1.2x < 4
2x < 4
x < 4/2
x < 2</span>
Answer:
Step-by-step explanation:
(a) 1.56×10^4 = 1.56×10000 = 15,600
(b) There are 3600 seconds in an hour, so Andrew's time was
15600 s/(3600 s/h) = 13/3 h = 4 1/3 h
1/3 hour is 20 minutes, so Evelyn's time of 4:16 is shorter than Andrew's time of 4:20.
<u>Given</u>:
The given function
which models the value of Mark’s car, where x represents the number of years since he purchased the car.
We need to determine the approximate value of Mark's car after 7 years.
<u>Value of the car:</u>
The value of the car after 7 years can be determined by substituting x = 7 in the function
, we get;



Rounding off to the nearest dollar, we get;

Thus, the approximate value of Mark's car after 7 years is $14278.
Hence, Option a is the correct answer.