Answer:
14. 70% of 20000 is 14000. 25% of 14000 is 3500. 3500 students applied.
15. The percentage of 4000 that 2600 equates to would be 65%.
16. 4% of 33000 is 1320.
16b. Double of 1320 is 2640.
17. 3% of 110 + 275 + 200 + 145 is 21.9. 97% of that is 711.1. Total is 730.
18. There are 1656 men working. Total of 1380 + 1656 is 3036. Two ways to solve this are:
Honestly I can't think of two. Sorry, my brain is completely fried today.
19. 760 in sales commissions to meet the wage amount.
20. The agency gets 21010. 30% of that is 6303. This is explained by owning a calculator or simple value elimination.
the list S describes all possible outcomes of the event.
the fourth option
two will get choosen, and the order matters.
1.
(x/2) - 7 = 11
2.
2x + 7 = 27
3.
2x - 5 = 25
Hope this helped!! (:
Answer:
a)
=0.89
b) 0.8413
Step-by-step explanation:
we know that




x - N(150, 20^2)

check

Answer:
y=0. 24x + 12. 7
Step-by-step explanation:
since you start with 12. 7 and gain .24 each year, you would multiply the years by. 24 and just add the 12. 7 I hope this makes sense. also I love your profile picture :)