There would be 6 shapes, and it would depend on what those shapes are since you wouldn't know the measurements.
27y^3 -343 starts out with 27y^3, and 343 is the cube of 7. Thus, we know immediately that 27y3 -343 is the diffeence of two squares.
The appropriate rule is a^3 - b^3 = (a - b)(a^2 + ab + b^2).
Here, we have 27y3 -343 = (3y - 7)(9y^2 + 12y + 49)
Choice (B) is true.
For (A): 5 is not a divisor of 14, whose only divisors are 1, 2, 7, and 14.
For (B): the factors of 10 are: 1, 2, 5, and 10. The factors of 15 are: 1, 3, 5, and 15. As we can see, the only, and greatest, common factor is 5.
For (C): 3 is not a factor of 13, which is a prime number.
For (D): again, 3 is not a factor of 14.
