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3 years ago

Which statement is true?

Mathematics

1 answer:

Nata [24]3 years ago

8 0

P(hemoglobin level between 9 and 11) = P(age between 25 and 35 years)..

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LaShea would like to invest her $100 in birthday money. Which option will give her the most money at the end of the investment p

Gnom [1K]

Third choice because 1,5 years at 7 percent would of been kore

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3 years ago

Read 2 more answers

Sweaters are $3 for $50. Leslie and her mother spent $100 on sweaters. How many did they buy

inn [45]

Answer:

Step-by-step explanation:

5 0

2 years ago

In triangle $ABC$, let angle bisectors $BD$ and $CE$ intersect at $I$. The line through $I$ parallel to $BC$ intersects $AB$ and

Umnica [9.8K]

Answer:

Step-by-step explanation:

If you work through a series of obscure calculations involving area and the radius of the incircle, they boil down to a simple fact:

... For MN║BC, perimeter ΔAMN = perimeter ΔABC - BC = AB+AC

.. = 17+24 = 41

_____

Wow! Thank you for an interesting question with a not-so-obvious answer.

_____

<em>A little more detail</em>

The point I that you have defined is the incenter—the center of an inscribed circle in the triangle. Its radius is the distance from I to any side, such as BC, for example.

If we use "Δ" to represent the area of the triangle and "s" to represent the semi-perimeter, (AB+BC+AC)/2, then the incircle has radius Δ/s. The area Δ can be computed from Heron's formula by ...

... Δ = √(s(s-a)(s-b)(s-c)) . . . . where a, b, c are the side lengths

For this triangle, the area is Δ = √38480 ≈ 196.1632 units². That turns out to be irrelevant.

The altitude to BC will be 2Δ/(BC), so the altitude of ΔAMN = (2Δ/(BC) -Δ/s). Dividing this by the altitude to BC gives the ratio of the perimeter of ΔAMN to the perimeter of ΔABC, which is 2s.

Putting these ratios and perimeters together, we get ...

... perimeter ΔAMN = (2Δ/(BC) -Δ/s)/(2Δ/(BC)) × 2s

... = (2/(BC) -1/s) × BC × s = 2s -BC

... perimeter ΔAMN = AB +AC

8 0

3 years ago

How do you find the area of this composite figure?

Illusion [34]

If you notice the picture below

the composite figure is just a trapezoid sitting on top of a rectangle
and then, the rectangle has a triangular hole in it

so.. get the area of the trapezoid $\bf \textit{area of a trapezoid}=A=\cfrac{h}{2}(a+b)\qquad 
\begin{cases}
h=height\\
a,b=\textit{parallel sides or bases}
\end{cases}$

then get the area of the rectangle, which is just a 12x14
and then get the area of the triangle, which surely you know is 1/2 bh

then, subtract the triangle's area from the rectangle's area

and whatever is left, namely the difference, add that to the area of the trapezoid, and that's the composite's area

namely the area of the trapezoid plus the rectangle's, minus the triangle's

6 0

3 years ago

When James family went on the road to the carnival they were stuck in traffic. After a 20 minutes they are were 30 more miles le

Assoli18 [71]

Answer:

They would be 5.5 miles away because if you take 20 divided by 20 to get 1 minute you would have to take 30 divided by 20 to get 1.5 miles per 1 minute. Then you would have to take 1 times 35 to get 35 minutes and you would have to take 1.5 times 35 to get 52.5. Then lastly you would take 58 miles and subtract 52.5 to get 5.5 miles therefor your answer would be 5.5 miles.

Step-by-step explanation:

5 0

3 years ago