The object needs 10.58 minutes to travel 1 4/5 if the object is traveling at a steady speed of 10 1/5 mi/h.
<h3>What is the distance?</h3>
Distance is a numerical representation of the distance between two items or locations. Distance refers to a physical length or an approximation based on other physics or common usage considerations.
It is given that:
An object is traveling at a steady speed of 10 1/5 mi/h.
u = 10 1/5 min/h
u = 51/5 min/h
As we know, the speed-distance relationship:
time = distance/speed
distance = 1 4/5 = 9/5
time = (9/5)/(51/5)
time = 9/51 hours
time = (9/51)60
time = 10.58 minutes
Thus, the object needs 10.58 minutes to travel 1 4/5 if the object is traveling at a steady speed of 10 1/5 mi/h.
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7+d=19 is the answer
subtract 7 from each side d=19-7
d=12
Explanation: 3 x 2 + 10 x + 3 We can Split the Middle Term of this expression to factorise it. In this technique, if we have to factorise an expression like a x 2 + b x + c , we need to think of 2 numbers such that: N 1 ⋅ N 2 = a ⋅ c = 3 ⋅ 3 = 9 and, N 1 + N 2 = b = 10 After trying out a few numbers we get: N 1 = 9 and N 2 = 1 9 ⋅ 1 = 9 , and 9 + ( 1 ) = 10 3 x 2 + 10 x + 3 = 3 x 2 + 9 x + 1 x + 3 = 3 x ( x + 3 ) + 1 ( x + 3 ) ( 3 x + 1 ) ( x + 3 ) is the factorised form for the expression.
c
, we need to think of 2 numbers such that:
N
1
⋅
N
2
=
a
⋅
c
=
3
⋅
3
=
9
and,
N
1
+
N
2
=
b
=
10
After trying out a few numbers we get:
N
1
=
9
and
N
2
=
1
9
⋅
1
=
9
, and
9
+
(
1
)
=
10
3
x
2
+
10
x
+
3
=
3
x
2
+
9
x
+
1
x
+
3
=
3
x
(
x
+
3
)
+
1
(
x
+
3
)
(
3
x
+
1
)
(
x
+
3
)
is the factorised form for the expression.
Answer:
V ≈ 68.63 cm³
Step-by-step explanation:
the volume (V) of a sphere is calculated as
V = 
πr³
the volume of a hemisphere is half the volume of a sphere, so
V = 
× πr³ = 
πr³ , then
V = π × 3.2³
= π × 32.768
≈ 68.63 cm³ ( to 2 dec. places )
