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3 years ago

Which of the following is an arithmetic sequence

Mathematics

2 answers:

nlexa [21]3 years ago

7 0

2,4,8,16,32B,3,6,9 etc this are arithmetic sequence

kodGreya [7K]3 years ago

4 0

Answer:

First one.

-3 is added to the previous term.

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PLEASE HELP !! ILL GIVE BRAINLIEST *EXTRA POINTS*.. IM GIVING 40 POINTS !! DONT SKIP :((.

grandymaker [24]

Answer:

y = x + 12

Step-by-step explanation:

y -16 = 1(x-4)

y -16 = x -4

y =x +12

5 0

3 years ago

Read 2 more answers

Which equations represents a line that passes through (4, 1/3) and has a slope of 3/4

docker41 [41]

Answer:

y = 3/4x - 8/3

Step-by-step explanation:

y = 3/4x + b

1/3 = 3/4(4) + b

1/3 = 3 + b

-8/3 = b

6 0

3 years ago

Read 2 more answers

Find the fifth term in the sequence that is defined as follows a1=1. An=3an-1+2

faltersainse [42]

The fifth term in the sequence would be 161.

Step-by-step explanation:

We have to find the fifth term in the sequence $an=3a(n-1)+2$

Given that

a1 = 1 (that is the first term)

If we follow the formula, the value of every term depends on the value of immediate lower term. Therefore, the a2 can be calculated by putting 2 in place of n in above equation

$a2=3a(2-1)+2$

$a2=3a1+2$

$a2=3(1)+2$ as a1 = 1

$a2=5$

Similarly,

$a3=3a(3-1)+2$

$a3=3a2+2$

$a3=3(5)+2$ as a2 = 5

$a3=17$

and

$a4=3a(4-1)+2$

$a4=3a3+2$

$a4=3(17)+2$ as a3= 17

$a4=53$

and

$a5=3a(5-1)+2$

$a5=3a4+2$

$a5=3(53)+2$ as a4 = 53

$a5=161$

Therefore, the fifth term in the sequence would be 161.

Learn more:

The following links have more information about sequencing

brainly.com/question/7221312

Keywords: sequence, arithmetic series

#learnwithBrainly

6 0

4 years ago

2(a³+b²+11)+1(3+a³+b+11)

Ann [662]

Answer:

$2(a^3+b^2+11)+1(3+a^3+b+11)=3a^3+2b^2+b+36$

Step-by-step explanation:

I assume that you need simplification of the given expression.

The given expression is:

$2(a^3+b^2+11)+1(3+a^3+b+11)$

Using distributive property and multiplying 2 inside the parenthesis and 1 inside the other parenthesis. This gives,

$2(a^3+b^2+11)=2\times a^3+2\times b^2+2\times 11\\2(a^3+b^2+11)=2a^3+2b^2+22\\\\1(3+a^3+b+11)=1\times 3+1\times a^3+1\times b+1\times 11\\1(3+a^3+b+11)=3+a^3+b+11=a^3+b+14$

Therefore, $2(a^3+b^2+11)+1(3+a^3+b+11)$ is equal to:

$2a^3+2b^2+22+a^3+b+14$

Now, combining like terms using the commutative property of addition, we get:

$=(2a^3+a^3)+2b^2+b+(22+14)\\=3a^3+2b^2+b+36$

Therefore, the simplified form is $3a^3+2b^2+b+36$

8 0

4 years ago

Help on this question please.

user100 [1]

Answer:

a) P = 6x + 13//

b) i) x = 5//

ii) 9//

Step-by-step explanation:

a) P = 2(x+2) + 2(2x-1) + 3 + 8 m

= 2x+4 + 4x-2 + 3 + 8

= 6x + 13//

b) i) P = 43 m

43 = 6x + 13

43-13 = 6x

30 = 6x

6 6

x = 5//

ii) longest side = (2x-1) m

2 × 5 - 1

10-1 = 9//

4 0

3 years ago