All categories

3 years ago

How do you solve this?!!

Mathematics

2 answers:

sergejj [24]3 years ago

8 0

Answer:

I dont know try asking ur parents (I'm so sry that sounded mean)

spin [16.1K]3 years ago

7 0

Try scanning it on this app, or look it up on google. Hope this helps :)

You might be interested in

How do I multiply 89 x 38 by using partial products? PLEASE ANSWER FAST

olga_2 [115]

Answer:

The result after partial products of 89 x 38 is 3382

Step-by-step explanation:

We need to solve 89 x 38 using partial products.

In Partial products we divide each term such that 89 can be written as 80 and 9 while 38 can be written as 30 and 8

We will multiply each term with other and then find their sum.

Multiplication is shown in figure attached.

Now adding the results of each cell in the table:

2400+640+270+72= 3382

So, the result after partial products of 89 x 38 is 3382.

Learn More:

You can learn more about partial products at:

brainly.com/question/10666510

brainly.com/question/4282963

brainly.com/question/13174282

Keywords: Partial products, product

#learnwithBrainly

5 0

3 years ago

The quotient of 2 numbers, p and q.

BabaBlast [244]

Answer:

p/q = x

Step-by-step explanation:

3 0

3 years ago

Find all roots: x^3 + 7x^2 + 12x = 0 Show all work and check your answer.

Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

Solution:

We have been given a cubic polynomial.

$x^{3}+7 x^{2}+12 x=0$

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

$x^{3}+7 x^{2}+12 x=0$

$x\left(x^{2}+7 x+12\right)=0$ ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

$x^{2}+7 x+12=0$

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

$\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}$

Therefore, the two roots are:

$\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}$

And,

$\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}$

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0

3 years ago

Who was the first president of united state

STatiana [176]

George Washington
...............

7 0

3 years ago

Read 2 more answers

Plz help, thank you!!!

dangina [55]

The slope should be 3/5 because the rise over run using the points (0,3) and (5,6) result in 3/5.

6 0

4 years ago