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Hoochie [10]
4 years ago
6

Determine whether the statement is true or false. If it is true, explain why. If it is false, explain why or give an example tha

t disaproves the statement.
If Ax=ax for a square matrix A, vector x, and scalar a, where x=/0, then a is an eigenvalue of A.
Mathematics
1 answer:
shtirl [24]4 years ago
4 0

Answer:

True

Step-by-step explanation:

This statement is true, basically by the definition of eigenvalue. An eigenvalue is a scalar λ such that there exist a nonzero vector v which satisfies Av = λv. Naturally, the given value a satisfies this hypothesis, hence it is an eigenvalue, as we wanted to show.

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3 years ago
K/3.8 + 57.6 = 28.3<br> The value of k is =
Usimov [2.4K]

Answer:

k = -111.34

Step-by-step explanation:

In this question, you will solve for k.

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k/3.8 = -29.3

To get "k" by itself, multiply both sides by 3.8 to eliminate the fraction.

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3 years ago
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kobusy [5.1K]

Answer:

16 1/7

Step-by-step explanation:

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3 years ago
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pantera1 [17]

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