Answer:
Given - PS is parallel to QR
angle QPS is congruent to angle SRQ
To prove - PQ is congruent to RS
Solution -
In triangle PSQ and SQR
Angle PSQ = Angle SQR ( Interior Angle form by the parallel lines are equal i.e PQ is parallel to QR)
Angle P = Angle R (given)
SQ = SQ ( common)
PSQ = SQR ( prove above)
By ASA Congruence criteria Triangle PQS is congruent to triangle QRS
By CPCT PS is congruent to RS
Hence, Proved
4/6=2/3
2/3+x/3+3/2
apply rule a/c+-b/c=(a+-b)/c
(2+x)/3+3/2 is your final answer
remove the parenthesis if you want i was just trying to show 2+x over 3
Answer:
-490
Step-by-step explanation:
= (10+5^2)*((5*-2)+9-3^3)/2
= (10+25)*((5*-2)+9-3^3)/2
= (35)*((5*-2)+9-3^3)/2
= 35*((5*-2)+9-3^3)/2
= 35*((-10)+9-3^3)/2
= 35*(-10+9-3^3)/2
= 35*(-10+9-27)/2
= 35*(-1-27)/2
= 35*(-28)/2
= 35*-28/2
= -980/2
= -490
Answer:
Supplementary Angles: AOC and COD
Complementary Angles: COB and COD
Vertical Angles: AOE and COD
Adjacent Angles not supplementary or complementary: AOB and BOC
Step-by-step explanation:
