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geniusboy [140]
3 years ago
8

The surface area of an oil spill gets 105% larger every day, represented by the function s(x) = (1.05)x − 1. On the first day, i

t covered an area of 31 square meters. Which function would be used to find the area of the oil spill on the 15th day?
Mathematics
1 answer:
Keith_Richards [23]3 years ago
7 0

Answer:

f(d) = 31 × 1.05^(t-1)

31(1.05^(15-1))

61.3778795826

61.4 m²

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2 2/10 x 6 2/5 please help me!!!!! Thank you!!!
evablogger [386]
The answer is 24/25.
8 0
3 years ago
Find all the critical points of h(x) = x^3 − 3x^4 and categorize them as local
neonofarm [45]

Answer:

0 is an inflection point

1/4 is a local maximum.

Step-by-step explanation:

To begin with you find the first derivative of the function and get that

h'(x) = 3x^2 - 12x^3

to find the critical points you equal the first derivative to 0  and get that

3x^2 - 12x^3 = 0, x =  0,1/4

To find if they are maximums or local minimums you use the second derivative.

h''(x) = 6x-36x^2

since h''(0) = 0 is neither an inflection point, and since h''(1/4) = -3/4 then 1/4 is a maximum.

6 0
3 years ago
He determines that 6 is an extraneous solution because the difference of the numerators is 6, so the 6s cancel to 0. which best
seropon [69]

The question is incomplete. Completed question is given below the answer.

His solution for x is correct, but in order for 6 to be an extraneous solution, one denominator has to result in 0 when 6 is substituted for x.

Given  

Then the solution follows thus:

Step 1: 8(x – 4) = 2(x + 2)

Step 2: 4(x – 4) = (x + 2)

Step 3: 4x – 16 = x + 2

Step 4: 3x = 18

Step 5: x = 6

It can be seen that his solution is correct. But 6 is not an extraneous solution.

An extraneous solution is a solution to an equation that emerges from the process of solving the problem but is not a valid solution to the original problem.

When 6 is substituted into the original equation, the original equation holds.

Therefore, his solution for x is correct, but in order for 6 to be an extraneous solution, one denominator has to result in 0 when 6 is substituted for x.

Learn more about extraneous solution here: brainly.com/question/3751209

#SPJ4

Completed question:-

A student solves the following equation for all possible values of x:His solution is as follows:

Step 1: 8(x – 4) = 2(x + 2)

Step 2: 4(x – 4) = (x + 2)

Step 3: 4x – 16 = x + 2

Step 4: 3x = 18

Step 5: x = 6

He determines that 6 is an extraneous solution because the difference of the numerators is 6, so the 6s cancel to 0.

Which best describes the reasonableness of the student’s solution?

His solution for x is correct and his explanation of the extraneous solution is reasonable.

His solution for x is correct, but in order for 6 to be an extraneous solution, both denominators have to result in 0 when 6 is substituted for x.

His solution for x is correct, but in order for 6 to be an extraneous solution, one denominator has to result in 0 when 6 is substituted for x.

His solution for x is incorrect. When solved correctly, there are no extraneous solutions.

5 0
2 years ago
What is the first operation used to evaluate 5+7•6-2÷4
Kisachek [45]

Multiply 7x6 since when using pemdas, multiplication and division can be inverted, i.e. if multiplication is before division then you multiply and vice versa.


Hope this helps!

3 0
3 years ago
John into friends are going out for pizza for lunch they split one pizza in three large pizza cost $12 he spent a total of 16.95
grin007 [14]

The large drink is 4$

7 0
3 years ago
Read 2 more answers
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