Question

In this triangle Cos A / Cos B = ?

Answer 1

For this case we have that by definition of trigonometric relations of rectangular triangles, that the cosine of an angle is given by the leg adjacent to the angle on the hypotenuse of the triangle. Then, according to the figure we have:

$Cos (A) = \frac {3} {4.24} = 0.707547169811\\Cos (B) = \frac {3} {4.24} = 0.707547169811$

So:

$\frac {Cos (A)} {Cos (B)} = \frac {0,707547169811} {0,707547169811} = 1$

Answer:

$\frac {Cos (A)} {Cos (B)} = 1$