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kiruha [24]
4 years ago
11

Simplify

Mathematics
2 answers:
Vika [28.1K]4 years ago
7 0
4 to the power of 15
Natasha2012 [34]4 years ago
5 0
The rule when an exponent is raised by another exponent is:

(a^b)^c = a^(b*c)

In this case:

(4^3)^5

4^(3*5)

4^15
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What are the solutions to 2 * (x - 7) ^ 2 = 32 ?
amm1812

Answer:

11 is answer

2 * (x - 7) ^ 2 = 32

(x-7)²=32/2

(x-7)²=16

x-7=√16

x-7=4

x=7+4=11

4 0
3 years ago
Read 2 more answers
Given Triangle IFN congruent to Triangle SJP, name all the pairs of corresponding parts.
Gemiola [76]
Sides
IF=SJ
FN=JP
NI=PS

Angles
I=S
F=J
N=P
5 0
3 years ago
( brainlies ) Can somebody help me with this?
Gekata [30.6K]

Answer:
(a)

Area: 930 meters(m)

Perimeter: 122 meters(m)

(b)

Area: 616 centimeters(cm)

Perimeter: 116 centimeters(cm)

(c)

Area: 1008 millimeters(mm)

Perimeter: 128 millimeters(mm)

Explanation:

Area = length x width

Perimeter = length+width+length+width

Area for (a) is then 31 times 30 = 930
Area for (b) is then 44 times 14 = 616
Area for (c) is then 36 times 28 = 1008

Perimeter for (a) is 31+30+31+30=122

Perimeter for (b) is 44+14+44+14=116

Perimeter for (c) is 36+28+36+28=128

4 0
3 years ago
Read 2 more answers
jason runs 440 yards in 75 seconds.At this rate how many minutes does it take him to run a mile? (1 mile = 1,760 yards)​
Zepler [3.9K]

Answer: 5 minutes

Step-by-step explanation:

We know that 1760 yards are in a mile. We can convert the given info into a proportion. 440/75 = 1760/x, where x is the number of seconds it takes to run a mile. Cross-multiply to get 440x = 75*1760. Divide both sides by 440 to get x = 75*4 = 300 seconds. The problem asks for how many minutes so you have to convert 300 seconds to minutes. To do this, we have to divide 300 by 60 to get 5 minutes.

7 0
4 years ago
2x-5) = 2(x-5) One Solution Infinitely Many Solutions No Solution 5x + 4) = 5(1-6) 5(x + 4) = 3(x-6) 4x - 2) = 4(x + 2) x + 2(x-
Gekata [30.6K]

9514 1404 393

Answer:

  top down: ∞, 0, 1, 0, ∞

Step-by-step explanation:

The equation will have infinite solutions when the left side and right side simplify to the same expression. This is the case for the first and last expressions listed.

  2(x -5) = 2(x -5) . . . . expressions are already identical

  x +2(x -5) = 3(x -2) -4  ⇒  3x -10 = 3x -10 . . . the same simplified expression

__

The equation will have no solutions when the x-coefficients are the same, but there are different added constants.

  5(x +4) = 5(x -6)  ⇒  x +4 = x -6  . . .  not true for any x

  4(x -2) = 4(x +2)  ⇒  x -2 = x +2  . . .  not true for any x

__

The equation will have one solution when coefficients of x are different.

  5(x +4) = 3(x -6)  ⇒  2x = -38  ⇒ x = -19

4 0
3 years ago
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