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3 years ago

Some help I keep getting this freaking question wrong!!!!!

Mathematics

1 answer:

SpyIntel [72]3 years ago

7 0

Okay, so there's 100 pennies in a dollar and 100 x 200 = 20,000

Then to find our amount of millimeters we need to do 20,000 x 1.55 = 31,000 millimeters = 31 meters

Hope it helps!

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Find derivative problem<br> Find B’(6)

dalvyx [7]

Answer:

$B^\prime(6) \approx -28.17$

Step-by-step explanation:

We have:

$\displaystyle B(t)=24.6\sin(\frac{\pi t}{10})(8-t)$

And we want to find B’(6).

So, we will need to find B(t) first. To do so, we will take the derivative of both sides with respect to x. Hence:

$\displaystyle B^\prime(t)=\frac{d}{dt}[24.6\sin(\frac{\pi t}{10})(8-t)]$

We can move the constant outside:

$\displaystyle B^\prime(t)=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)]$

Now, we will utilize the product rule. The product rule is:

$(uv)^\prime=u^\prime v+u v^\prime$

We will let:

$\displaystyle u=\sin(\frac{\pi t}{10})\text{ and } \\ \\ v=8-t$

Then:

$\displaystyle u^\prime=\frac{\pi}{10}\cos(\frac{\pi t}{10})\text{ and } \\ \\ v^\prime= -1$

(The derivative of u was determined using the chain rule.)

Then it follows that:

$\displaystyle \begin{aligned} B^\prime(t)&=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)] \\ \\ &=24.6[(\frac{\pi}{10}\cos(\frac{\pi t}{10}))(8-t) - \sin(\frac{\pi t}{10})] \end{aligned}$

Therefore:

$\displaystyle B^\prime(6) =24.6[(\frac{\pi}{10}\cos(\frac{\pi (6)}{10}))(8-(6))- \sin(\frac{\pi (6)}{10})]$

By simplification:

$\displaystyle B^\prime(6)=24.6 [\frac{\pi}{10}\cos(\frac{3\pi}{5})(2)-\sin(\frac{3\pi}{5})] \approx -28.17$

So, the slope of the tangent line to the point (6, B(6)) is -28.17.

5 0

3 years ago

- Round each number to four decimal places: a. 5.16 b. 5.27

DochEvi [55]

Answer:

wym by 4 decimal places

Step-by-step explanation:

5 0

2 years ago

2. Jacob deposited $6,000 into an account that offers 4.5% interest compounded annually.

Llana [10]

Answer: a

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Write the equation of a Line that is perpendicular to y=5/2x+3 and passes

koban [17]

Answer:

Step-by-step explanation:

Slope of perpendicular lines = -1

y = 5/2x + 3

$m_{1}=\frac{5}{2}\\\\m_{1}*m_{2}=-1\\\\$

$m_{2}=$ -1 ÷ $m_{1}$

= $-1*\frac{2}{5}=\frac{-2}{5}$

(-3 , -5)

Equation of the required line: y - y₁ = m(x -x₁)

y - [5] = $\frac{-2}{5}(x - [-3])\\$

$y+5=\frac{-2}{5}x + 3*\frac{-2}{5}\\\\y+5=\frac{-2}{5}x-\frac{6}{5}\\\\ y =\frac{-2}{5}x-\frac{6}{5}-5\\\\ y = \frac{-2}{5}x-\frac{6}{5}-\frac{5*5}{1*5}\\\\ y = \frac{-2}{5}x-\frac{6}{5}-\frac{25}{5}\\\\\\ y=\frac{-2}{5}x-\frac{31}{5}$

5 0

3 years ago

URGENT I need the answers for this

Leona [35]

Answer:

1 squared and 1 x squared

Step-by-step explanation:

7 0

3 years ago