are in that situation pls tell me
Based on the characteristics of <em>linear</em> and <em>piecewise</em> functions, the <em>piecewise</em> function
is shown in the graph attached herein. (Correct choice: A)
<h3>How to determine a piecewise function</h3>
In this question we have a graph formed by two different <em>linear</em> functions. <em>Linear</em> functions are polynomials with grade 1 and which are described by the following formula:
y = m · x + b (1)
Where:
- x - Independent variable.
- y - Dependent variable.
- m - Slope
- b - Intercept
By direct observation and by applying (1) we have the following <em>piecewise</em> function:

Based on the characteristics of <em>linear</em> and <em>piecewise</em> functions, the <em>piecewise</em> function
is shown in the graph attached herein. (Correct choice: A)
To learn more on piecewise functions: brainly.com/question/12561612
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Answer:

Step-by-step explanation:
We have been given that when a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a rate of 0.7 meters per hour. We are asked to find the approximate radius of tank in meters.
We will use volume of cylinder formula to solve our given problem as:
, where,
r = Radius,
h = Height of cylinder.
Since the level of water in the tank rises at a rate of 0.7 meters per hour, so height of cylinder would be
meters at
.
Upon substituting these values in above formula, we will get:





Now, we will take positive square root of both sides as radius cannot be negative.


Therefore, radius of tank would be approximately square root of 10 m.
Answer:
The answer is B
Step-by-step explanation:
8 times 12 = 96
2L + 2W = 40
2(8) + 2(12) = 40
because
16 + 24 = 40
Hope this helps!
Step-by-step explanation:
Hey, there!!
Given that,

{ we can write (a^2-4) as (a^2 - 2^2) also as (x^2- 9) can be written as (x^2 - 3^2)}.

We have a^2-b^2= (a+b) (a-b), so keep same formula on it.

(x+3) in numerator and denominator gets cancelled,

Therefore, (x-3) is the final value.
<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>