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2 years ago

Natalie earned $200 in interest and 30 months with a beginning balance of $1040. What was her interest rate?

Mathematics

1 answer:

rjkz [21]2 years ago

5 0

The interest rate is 7.69%

Step-by-step explanation:

Given

Interest = $200

Time = t = 30 months

Time will be converted into years as the rate is applied yearly

So,

1 year = 12 months

30 months = 30/12 years = 2.5 years

Principal amount = $1040

The formula for interest is:

$I = P*r*t$

Putting the values

$200 = 1040 * r * 2.5\\200 = 2600r\\r = \frac{200}{2600}\\r = 0.076923$

Converting into percentage:

r = 7.6923

Rounding off to nearest hundredth

r = 7.69%

Hence,

The interest rate is 7.69%

Keywords: Interest, percentage

Learn more about interest at:

#LearnwithBrainly

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A company is producing two types of ski goggles. Thirty percent of the production is of type A, and the rest is of type B. Five

exis [7]

Answer:

$\dfrac{14}{29}$

Step-by-step explanation:

Let P(A) be the probability that goggle of type A is manufactured

P(B) be the probability that goggle of type B is manufactured

P(E) be the probability that a goggle is returned within 10 days of its purchase.

According to the question,

P(A) = 30%

P(B) = 70%

P(E/A) is the probability that a goggle is returned within 10 days of its purchase given that it was of type A.

P(E/B) is the probability that a goggle is returned within 10 days of its purchase given that it was of type B.

$P(A \cap E)$ will be the probability that a goggle is of type A and is returned within 10 days of its purchase.

$P(B \cap E)$ will be the probability that a goggle is of type B and is returned within 10 days of its purchase.

$P(E \cap A) = P(A) \times P(E/A)$

$P(E \cap A) = \dfrac{30}{100} \times \dfrac{5}{100}\\\Rightarrow P(E \cap A) = 1.5 \%$

$P(E \cap B) = P(B) \times P(E/B)$

$P(E \cap B) = \dfrac{70}{100} \times \dfrac{2}{100}\\\Rightarrow P(E \cap B) = 1.4 \%$

$P(E) = 1.5 \% + 1.4 \% \\P(E) = 2.9\%$

If a goggle is returned within 10 days of its purchase, probability that it was of type B:

$P(B/E) = \dfrac{P(E \cap B)}{P(E)}$

$\Rightarrow \dfrac{1.4 \%}{2.9\%}\\\Rightarrow \dfrac{14}{29}$

So, the required probability is $\dfrac{14}{29}.$

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3 years ago

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Answer:

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Step-by-step explanation:

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Lets get rid of the 0 for now

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That is 15 added to itself 0 times so it is 15

Now lets put the 0 back

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150

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Answer:

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