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valina [46]
3 years ago
12

6 multiplication problems that ar involved in the solving of 325×89​

Mathematics
1 answer:
gogolik [260]3 years ago
4 0

325*89.1

Let's decompose this into:

325 = 300 + 25

89.1 = 80 + 9 + 0.1

Then we have the multiplication:

(300 + 25)*(80 + 9 + 0.1)

Let's distribute the multiplication:

300*80 + 300*9 + 300*0.1 + 25*80 + 25*9 + 25*0.1

So now we have 6 multiplications that are a lot easier to solve than the initial one that we had.

Then the list of six multiplications involved in solving this problem are:

300*80 = 24,400

300*9 = 2,700

300*0.1 = 30

25*80 = 2,000

25*9 = 225

25*0.1 = 2.5

Now we add all of those and get:

325*89.1 = 24,400 + 2,700 + 30 + 2,000 +  225 + 2.5 = 28,957.5

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The answers to the given addition operations are

7) 6 Hundredths add to 4 tenths add to 6 ones is equal to 6.46

8) 82 Hundredths add to 9 tenths add to 4 tens is equal to 41.72

<h3>Addition operation </h3>

From the question, we are to add the given numbers

7. 6 Hundredths add to 4 tenths add to 6 ones is equal to

6 Hundredths = 0.06

4 tenths = 0.4

6 ones = 6

Thus, we get

0.06 + 0.4 + 6 = 6.46

8. 82 Hundredths add to 9 tenths add to 4 tens is equal to

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9 tenths = 0.9

4 tens = 40

Thus, we get

0.82 + 0.9 + 40 = 41.72

Hence, the answers to the given addition operations are

7) 6 Hundredths add to 4 tenths add to 6 ones is equal to 6.46

8) 82 Hundredths add to 9 tenths add to 4 tens is equal to 41.72

Learn more on Addition operation here: brainly.com/question/4248979

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