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2 years ago

To the nearest hundredth, how many cm are in 16 in? (1 in = 2.54 cm)

1 answer:

7 0

Well ok all you need to do is multiply 2.54 and 16 then round.

2.54
x 16
--------
1524
+2540
-------------
→ 40.64 ←
This answer is already rounded to the nearest hundredth. I hope this helps love! :)

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The ratio of boys to girls in the 10th grade is 8 to 13. If there are 91 girls in 10th grade, then how many boys are there?

IRINA_888 [86]

Answer: There are 56 boys in the 10th grade

Step-by-step explanation:

Step 1

ratio of boys to girls in the 10th grade is 8 :13

Number of girls= 91

To find the number of boys, we first find the total number of boys and girls in the 10th grade

Step 2

Now the total ratio= 8 +13=21

Number of girls = ratio of girls/ total ratio x Total number of students

91=13/ 21 x Total number of students

Total number of students =21 x 91 / 13 =147

Step 3

Therefore Number of boys =ratio of boys/ total ratio x Total number of student

8/21 x 147=56

6 0

3 years ago

You can buy 5 stickers for $3. Write a proportion that gives the cost c if you buy 12 stickers.

Reptile [31]

Answer:

$7.5

Step-by-step explanation:

Let

Quantity of stickers=x

Price of stickers=y

5 stickers cost $3

12 stickers cost $y

x/y = x/y

5/3 = 12/y

Cross product

5y=12*3

5y=36

Divide both sides by 5

5y/5 = 36/5

y=7.5

12 stickers= $7.5

Therefore, the price of 12 stickers= $7.5

5 0

3 years ago

The circle below is center Ed at O. Decide which length,if any, is definitely the same as the length. a) AD. b) BC. Justify your

Mars2501 [29]

Answer:

Point O is the center of the circle.

Part (a)

$\overline{A\:\!F}$ is a chord.

$\overline{OD}$ is a segment of the radius and is perpendicular to $\overline{A\:\!F}$

If a radius is perpendicular to a chord, it bisects the chord (divides the chord into two equal parts).

Therefore, $\overline{AD}=\overline{DF}$

Part (b)

If $\overline{BE}$ was extended past point E to touch the circumference it would be a chord.

As $\overline{OC}$ is perpendicular to $\overline{BE}$ , it would bisect the chord, but as $\overline{BE}$ is only a portion of a chord, $\overline{OC}$ does not bisect $\overline{BE}$ .