Question

Quadratic Functions: Standard Form

Answer 1

$f(x)=x^2+12x+11$

Find the x-intercept, f(x) = 0

$x^2+12x+11=0\\(x+11)(x+1)=0\\x=-11,-1$

There we get the x-intercepts, what about y-intercept? That's easy, (0,11). You don't even need to calculate to get the y-intercept as from

$f(x)=ax^2+bx+c$ (a=/0)

The y-intercept is "c" So if c = 2 then y-intercept is (0,2)

Or if you want to calculate for y-intercept.

then x=0

$f(0)=0^2+12(0)+11\\f(0)=0+0+11\\f(0)=11$

There, we get the y-intercept which is (0,11).

Therefore, x-intercepts are (-11,0) and (-1,0)

y-intercept is (0,11)

and yeah, you kinda of got it right.