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3 years ago

Consider a set of mobile computing clients in a certain town who each

Computers and Technology

1 answer:

poizon [28]3 years ago

5 0

Answer: answer given in the explanation

Explanation:

We have n clients and k-base stations, say each client has to be connected to a base station that is located at a distance say 'r'. now the base stations doesn't have allocation for more than L clients.

To begin, let us produce a network which consists of edges and vertex

Network (N) = (V,E)

where V = [S, cl-l, - - - - cl-n, bs-l - - - - - - bs-k, t]

given that cl-l, - - - - - cl-n represents nodes for the clients

also we have that bs-l, - - - - - bs-k represents the nodes for base station

Also

E = [ (s, cl-i), (cl-i,bs-j), (bs-j,t)]

(s, cl-i) = have capacity for all cl-i (clients)

(cl-i,bs-j) = have capacity for all cl-i clients & bs-j (stations)

⇒ using Fond Fulkorson algorithm we find the max flow in N

⇒ connecting cl-i clients to bs-j stations

like (cl-i, bs-j) = 1

if f(cl-i, bs-j) = 0

⇒ say any connection were to produce a valid flow, then

if cl-i (clients) connected f(s,cl-i) = 1 (o otherwise)

if cl-i (clients) connected to bs-j(stations) f(cl-i,bs-j) = 1 (o otherwise)

f(bs-j,t) = no of clients (cl-i) connected to bs-j

⇒ on each node, the max flow value (f) is longer than the no of clients that can be connected.

⇒ create the connection between the client and base station i.e. cl-l to base bs-j iff f(cl-i, bs-j) = 1

⇒ when considering the capacity, we see that any client cannot directly connect to the base stations, and also the base stations cannot handle more than L clients, that is because the load allocated to the base statsion is L.

from this, we say f is the max no of clients (cl-i) that can be connected if we find the max flow, we can thus connect the client to the base stations easily.

cheers i hope this helps

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Anastaziya [24]

Of course there is. On a simple level, consider a parent trying to locate their missing child. Someone might break into their social media accounts to see if there are messages that might help determine their whereabouts.

Consider a website hosting inappropriate pictures of children. Breaking into the server hosting the files and removing them is 100% ethical.

I'm sure you can think of more examples.

7 0

2 years ago

The /tmp directory is a temporary directory and will not exist on a system at all times. True or False?

jeka94

Answer:

False.

Explanation:

The /tmp directory is a directory that contains files that are required temporarily and also for temporary storage of data.The data inside the /tmp directory gets deleted when the system boots or shuts down.Since the directory exists permanently the content inside it is temporary.

So we can conclude that the answer is False.

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3 years ago

How an operating system allocates system resources in a computer

Whitepunk [10]

Answer:

The Operating System allocates resources when a program need them. When the program terminates, the resources are de-allocated, and allocated to other programs that need them

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3 years ago

Integers and booleans. Write a program RightTriangle that takes three int command-line arguments and determines whether they con

icang [17]

Answer:

The programming language is not stated;

I'll answer using C++

#include<iostream>

#include<cmath>

using namespace std;

int main()

{

int side1, side2, side3;

cout<<"Enter the three sides of the triangle: "<<endl;

cin>>side1>>side2>>side3;

if(side1<=0 || side2 <= 0 || side3 <= 0) {

cout<<"Invalid Inputs";

}

else {

if(abs(pow(side1,2) - (pow(side2,2) + pow(side3, 2)))<0.001) {

cout<<"Right Angled";

}

else if(abs(pow(side2,2) - (pow(side1,2) + pow(side3, 2)))<0.001) {

cout<<"Right Angled";

}

else if(abs(pow(side3,2) - (pow(side2,2) + pow(side1, 2)))<0.001) {

cout<<"Right Angled";

}

else {

cout<<"Not Right Angled";

}

return 0;

}

Explanation:

The following line declares the three variables

int side1, side2, side3;

The next line prompts user for input of the three sides

cout<<"Enter the three sides of the triangle: "<<endl;

The next line gets user input

cin>>side1>>side2>>side3;

The following if condition checks if any of user input is negative or 0

if(side1<=0 || side2 <= 0 || side3 <= 0) {

cout<<"Invalid Inputs";

}

If otherwise

else {

The following if condition assumes that side1 is the largest and test using Pythagoras Theorem

if(abs(pow(side1,2) - (pow(side2,2) + pow(side3, 2)))<0.001) {

cout<<"Right Angled";

}

The following if condition assumes that side2 is the largest and test using Pythagoras Theorem

else if(abs(pow(side2,2) - (pow(side1,2) + pow(side3, 2)))<0.001) {

cout<<"Right Angled";

}

The following if condition assumes that side3 is the largest and test using Pythagoras Theorem

else if(abs(pow(side3,2) - (pow(side2,2) + pow(side1, 2)))<0.001) {

cout<<"Right Angled";

}

If none of the above conditions is true, then the triangle is not a right angles triangle

else {

cout<<"Not Right Angled";

}

}

return 0;

Download cpp

4 0

3 years ago

You are helping a friend in college with his network connection. He would like a high speed connection between his computers so

inna [77]

Solution :

Set up the router as follows:

On the Shelf, expand the Routers. And read the description for each of the devices. Drag the Ethernet $100/1000TX$ router with the firewall to the Workspace.

Connection of the router as follows:

Above the router, select the Back to switch to the back view of the router. Then select the cable currently connected to the wall plate and then drag it to a $LAN$ port on the router. Above the Dorm- $PC2$ computer, select $\text{back}$ to switch to the back view of the computer. On the Shelf, expand Cables. Select a Cat5e $RJ45$ cable. In the Selected Component window, drag the connector to the $LAN$ port on the computer. In the Selected Component window, drag the other connector to a $LAN$ port on the router. Select a Cat5e $RJ45$ cable. In the Selected Component window, drag a connector to the $WAN$ port on the router. In the Selected Component window, drag the other connector to the port on the wall plate.

Provide power to the router as follows:

On the Shelf, select the power adapter. In the Selected Component window, drag the DC power connector to the power port on the router. In the Selected Component window, drag the AC adapter connector to the surge protector. Above the router, select Front to switch to the front view to verify power and network activity lights.

Request new $TCP/IP$ information from the router for Dorm-PC as follows:

On the $\text{Dorm-PC}$ monitor, select Click to view $\text{Windows 10}$ .In the Search field on the taskbar, enter command prompt. Under Best Match, select Command Prompt. Enter $\text{ipconfig}$ /renew and press $\text{Enter}$ to request new $TCP/IP$ information from the router. In the notification area, right-click the Network icon and select Open Network and Sharing Center. The network information map should indicate an active connection to the Firewall Network and the internet.

Configure Windows Firewall on $\text{Dorm-PC}$ as follows:

In Network and Sharing, select Windows Firewall. From the left menu, select Turn Windows Firewall on or off. Under Private network settings, select Turn on Windows Firewall. Under Public network settings, select Turn on Windows Firewall. Click OK.

4 0

3 years ago