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Sloan [31]
3 years ago
10

Which statement is true? Without the earth's moon, life on Earth would not be possible. The earth's moon is the smallest moon re

lative to its host planet. The earth's moon is thought to have formed when a Mars-sized planet collided with Earth during its final stages of planetary accretion. The earth's moon is the same size as the earth.
Mathematics
1 answer:
suter [353]3 years ago
5 0

Answer:

Why are you asking here?

Step-by-step explanation:

Anyways its in what you asked:

"The earth's moon is thought to have formed when a Mars-sized planet collided with Earth during its final stages of planetary accretion."

This is because, in my science class at least, our teacher taught us that a Mars sized object collided with earth, and the debris from this caused the moon to form. This is also highly likely in early solar systems, as they are very dangerous with many objects crashing and colliding with other objects.

"Without the earth's moon, life on Earth would not be possible."

Maybe? I don't know. I think False on this one because we don't yet know how life came into existence, where compounds turned into organic compounds or something like that.

"The earth's moon is the smallest moon relative to its host planet."

I think that's Mars's moons, so false(Don't know much about astronomy)

"The earth's moon is the same size as the earth."

Very, Very, VERY unlikely. This would cause both the Earth and the Moon to rip each other to shreds with their own gravity, and we would have serious planet sized-problems.

Hope this helps!

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A storage tank will have a circular base of radius r and a height of r. The tank can be either cylindrical or hemispherical​ (ha
Neko [114]

Answer:

Volume: \frac{2}{3}\pi r^3

Ratio: \frac{2}{9}r

Step-by-step explanation:

First of all, we need to find the volume of the hemispherical tank.

The volume of a sphere is given by:

V=\frac{4}{3}\pi r^3

where

r is the radius of the sphere

V is the volume

Here, we have a hemispherical tank: a hemisphere is exactly a sphere cut in a half, so its volume is half that of the sphere:

V'=\frac{V}{2}=\frac{\frac{4}{3}\pi r^3}{2}=\frac{2}{3}\pi r^3

Now we want to find the ratio between the volume of the hemisphere and its surface area.

The surface area of a sphere is

A=4 \pi r^2

For a hemisphere, the area of the curved part of the surface is therefore half of this value, so 2\pi r^2. Moreover, we have to add the surface of the base, which is \pi r^2. So the total surface area of the hemispherical tank is

A'=2\pi r^2 + \pi r^2 = 3 \pi r^2

Therefore, the ratio betwen the volume and the surface area of the hemisphere is

\frac{V'}{A'}=\frac{\frac{2}{3}\pi r^3}{3\pi r^2}=\frac{2}{9}r

6 0
3 years ago
Triangle ACB is the pre-image and triangle DFE is the image. What is the scale factor of the dilation?
Reika [66]

Answer:

½

Step-by-step explanation:

the scale factor of dilation = 6/12 = ½

7 0
3 years ago
T-6=8-t<br><br>how do solve? pls include steps
umka2103 [35]
First, add t to each side:
2t - 6 = 8
Add 6 to each side:
2t = 14
Divide both sides by 2:
t = 7

Hope this helps!! :)
8 0
3 years ago
It is about solving equations by substitution. if you can help plzzz
Lyrx [107]
Message me, and i can help more:)
6 0
3 years ago
Calculate the rate of change of the linear function that contains the points
Mandarinka [93]

Answer:

-2

Step-by-step explanation:

X1 Y1 X2 Y2

(-15, 30) (7, -14)

Y2-Y1 = -14-30 = -44 = -2

———————————————

X2-X1 = 7-(-15)= 22 = 1

3 0
3 years ago
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