Answer:
C. 1/(x^2 +1) > 0
Step-by-step explanation:
The cube of a negative number is negative, eliminating choices B and D for certain negative values of x.
1/x^2 is undefined for x=0, so cannot be compared to zero.
The value 1/(x^2+1) is positive everywhere, so that is the expression you're looking for.
1/(x^2 +1) > 0
Answer:
x=-1
Step-by-step explanation:
w-2=-8-5w
-2=-8-6w
+8 +8
6=-6w
divide 6 in both side
x=-1
hope this help.
Answer:
-4a +22b
Step-by-step explanation:
add the ones with same variable
Let x = adult tickets
Let y = children's tickets
x + y = 800
8x + 4y = 4,400
From the first eq, x = 800 - y, plug this in to the second eq
8(800-y) + 4y = 4,400
6400 - 8y + 4y = 4,400
2000 = 4y
500 = y
x = 800 - 500
x = 300
300 adult tickets were sold.
We can solve this using substitution.
because x-y=2.5
x=y+2.5
Now substitute x into other equation.
2(y+2.5)^2-2y=125
2y^2+10y+12.5-2y=125
2y^2+8y-112.5=0
Now comes the ugly part
y=-4+-sqrt(16+900)
y=-4+-sqrt916
y=-4+-2sqrt229
x=-1.5+-2sqrt229
