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Lilit [14]
3 years ago
11

Solve.

Mathematics
1 answer:
Mandarinka [93]3 years ago
6 0
8x+4 \leq -20 \\ 8x+4-4 \leq (-20)-4 \\ 8x \leq -24 \\  \frac{8x}{8}  \leq  \frac{-24}{8}  \\  \\ x \leq -3 \\ A
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Answer:

Area = 21 unit²

Step-by-step explanation:

We have one point of triangle = (0,0)

The other points can be solved, intersection means

              −3x²+20 = x²−16

               4x² = 36

               x² = 9

               x = ±3  

when x = 3,      y =  3²−16  = 9 -16 = -7  , point is (3,-7)

when x = -3,      y =  (-3)²−16  = 9 -16 = -7  , point is (-3,-7)

We need to find area of triangle with points  (0,0), (3,-7) and (-3,-7).

Area of triangle is given by

         Area =\frac{1}{2}\begin{vmatrix}0 & 0 & 1\\ 3 & -7 & 1\\ -3 & -7 & 1\end{vmatrix}

  Area = \frac{1}{2}\left ( 0(-7\times 1-(1\times -7))-0(3\times 1-(1\times -3))+1(3\times -7-(-3\times -7)\right )\\\\Area =\frac{1}{2}(-21-21)=-21=21unit^2

Area = 21 unit²

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