<h3>Answer: 36%</h3>
============================================
Explanation:
There are 20 blue cards out of 10+20+25 = 55 cards total.
Divide the 20 over 55 to get
20/55 = 0.363636...
where the "36"s go on forever
So 20/55 = 0.3636 approximately
Move the decimal point over 2 spots to go from 0.3637 to 36.37%
Then round to the nearest percent: 36.37% ---> 36%
The probability of getting a blue card is approximately 36%
Answer:
3.6000
Step-by-step explanation:
I did this three different ways I think this is right.
Box 1:0,3,6,9,12, Box 2: 0,1,2, 14. Box3:1,9,13,18, box4:4,5,7hope this helps
Consecutive integers are 1 apart
x,x+1,x+2
(x)(x+1)(x+2)=-120
x^3+3x^2+3x=-120
add 120 to both sides
x^3+3x^2+3x+120=0
factor
(x+6)(x^2-3x+20)=0
set each to zero
x+6=0
x=-6
x^2-3x+20=0
will yeild non-real result, discard
x=-6
x+1=-5
x+2=-4
the numbers are -4,-5,-6
use trial and error and logic
factor 120
120=2*2*2*3*5
how can we rearange these numbers in (x)(y)(z) format such that they multiply to 120?
obviously, the 5 has to stay since 2*5=10 which is out of range
so 2*2*2*3 has to arrange to get 3,4 or 4, 6 or 6,7
obviously, 7 cannot happen since it is prime
3 and 4 results in in 12, but 2*2*2*3=24
therfor answer is 4 and 6
they are all negative since negaive cancel except 1
the numbers are -4,-5,-6
