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belka [17]
3 years ago
5

Cruz's Frame shop makes. a mat by cutting out the inside of a rectangular mat board. Find the length and width of the original m

at if the area of the mat board is 148 square inches. the outside length and with are 2x-1 and x+6 the inside length and width are 2x-5 and x+2
Mathematics
1 answer:
My name is Ann [436]3 years ago
5 0

Answer:

length = 23 inches ; width = 18 inches.

Step-by-step explanation:

Length and width can be found from the following expression after solving for x. The expression is given by :

outside area - inside area = 148 square inches

(2·x - 1)·(x + 6) - (2·x - 5)·(x + 2) = 148  (On substitute length and width expressions. Each area is the product of length and width.)

⇒ 2·x² + 11·x - 6 - (2·x² - x - 10) = 148

⇒ 12·x + 4 = 148 .................(On simplifying the expression)

⇒ 12·x = 144

⇒ x = 12

Then the original length of the mat is given by substituting value of x in outside length expression :

2·x - 1 = 2·12 - 1 = 23 inches

and the original width of the mat is given by :

x + 6 = 12 + 6 = 18 inches

Hence, the overall dimensions of the original mat are 23 inches by 18 inches.

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Find the least common multiple of 8x³y6z, 6x5z², and<br> 10yzº.
kvv77 [185]

Answer:

The Least Common Multiple (LCM) of 8x^3y6z,6x5z^2, \text{ and } 10yz^0 \text{ is } 240 x^3yz^2

Step-by-step explanation:

<u>Definition of LCM</u>

The LCM of a, b , c is the smallest multiplier that is divisible by a, b and c

Here the three terms are :

8x^3y6z

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Factoring using prime factorization we get  8x^3y6z = 2.2.2.x^3.y.2.3.z³

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Factoring 10yz^0 we get

2 \;\cdot\; 5y                 (z^0 = 1)   (3)

The LCM is the multiple of each of the highest power in each factor

2^4\;.\;3\;.\;5\;.x^2\;.\;y\;.z^2 = 240 x^3yz^2

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