The incidence of cystic fibrosis, a recessive genetic disorder in the Caucasian population of United States, is
in every 2,500 individuals. Find the number of heterozygous carriers. (p + q = 1, p2 + 2pq + q2 =
Answer: The answer to your question is........ A, <u>Covalent </u>bonds
Explanation: Covalent bonds occur when atoms achieve stability by sharing electrons. Covalent bonds are often represented as single lines in chemical formulas.
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Answer:
The chemical bond energy of glucose is released as ATP and heat. This is the primary source of ATP for all aerobic organisms.
Answer:
Cool. Did you know I bathed my fish today
Answer:
50% wild type and 50% black i.e. 1:1 phenotypic ratio
Explanation:
Given, b+ = wild type allele
b = recessive allele
b+b+ = dominant wild type
b+b = heterozygous wild type
bb = recessive black
First cross: female b+b (wild type) X male bb (black) = bb, bb, b+b, b+b
Since bb and b+b are in 1:1 phenotypic ratio, 52 black and 58 wild type progeny are produced.
From this progeny second cross occurs between:
female bb (black) X male (wild type) b+b = bb, bb, b+b, b+b
Again the same 1:1 phenotypic ratio is obtained. Half of the progeny will be be black (bb), other half will be wild type (b+b).