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AysviL [449]
3 years ago
6

If a vehicle decreases in value from $30,000 to $23,500, what is the percent decrease?

Mathematics
2 answers:
loris [4]3 years ago
8 0

First you would subtract 30000 - 23,500 = 6500

Now divide 6500 by the original number

6500/30000= 0.22

Multiply by 100 to get percent

22% decrease

Jlenok [28]3 years ago
4 0
30,000 - 23,500 = 6,500
\frac{6500}{30000} \times 100\% \\ = \frac{650000}{30000} \\ = 21.66\%

The answer is 21.66% or 22% decrease.
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Answer:

length = 18 mt

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Step-by-step explanation:

Let the length of the field be x

width of the field be y

Hence

P=2(x+y)

P=56 (given)

56=2(x+y)

Dividing both sides by 2 we get

x+y=28   ---(A)

Also given that width of the parallelogram is 8 meters less than its length

Hence

y=x-8

or x-y=8   ---(B)

Adding A and B

2x=36

x=18

y=x-8

y=18-8=10

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Graph D.

Step-by-step explanation:

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Solve 3x + 23 + x = 7. x = −4 x = 4 x = −0.25 x = 0.25
Maksim231197 [3]
<h2>______________________________</h2><h2>Solve for x | Solution and Explanation </h2>

______________________________________________

Hello! So...

We are given the following:

Solve for x.

3x+23+x=7

====================

1. Group the like terms.

  • 3x+x+23=7

====================

2. Add similar elements (3x+x=4x).

  • 4x+23=7

====================

3. Subtract 23 from both sides.

  • 4x + 23 - 23 = 7 - 23

====================

4. Simplify.

  • 4x=-16

====================

5. Divide both sides by 4.

  • \frac{4x}{4} =\frac{-16}{4}

====================

6. Simplify.

  • x=-4 (aka. Option A)

====================

Hope this helps!

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Answer:

Larger for the sample of Canadians

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The sample of Canadians is smaller, it is expected that their sampling variability is larger than the sample of Canadians based on the rule that as the sample size increases, the standard deviation of the means decreases; and as the sample size decreases, the standard deviation of the sample means increases

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