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zalisa [80]
3 years ago
10

You draw two marbles without replacement from a bag containing 2 green marbles and 3 black marbles. What are the possible outcom

es?
Mathematics
1 answer:
Step2247 [10]3 years ago
7 0
2 greens
1 black 1 green
2 blacks
Hope this helps ;p have a nice day!

~pam
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PLEASE HELP VERY URGENT!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
diamong [38]

Q1.  Look at the picture.

C.\\y=-\dfrac{1}{3}x+3\\\\y=2x-4

Q2. Look at the picture.

A.\ 4-t

Q3.

Put the value of x = 2 to the equation 3x + y = 5:

3(2)+y=5

6+y=5       <em>subtract 6 from both sides</em>

y=-1\\\\F.\ -1

Q4.

\left\{\begin{array}{ccc}n=3m-11&(*)\\2m+3n=0&(**)\end{array}\right

Substitute (*) to (**):

2m+3(3m-11)=0            <em>use distributive property</em>

2m+(3)(3m)+(3)(-11)=0

2m+9m-33=0       <em>add 33 to both sides</em>

11m=33      <em>divide both sides by 11</em>

m=3

Put the value of m to (*):

n=3(3)-11\\\\n=9-11\\\\n=-2

C. (3,\ -2)

Q5.

w - width

3w - length

24 in - the sum of length and width

The equation:

w+3w=24

4w=24           <em>divide both sides by 4</em>

w=6\ in

3w=3(6)=18\ in

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7 0
3 years ago
Read 2 more answers
Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are sel
Andre45 [30]

Answer:

Step-by-step explanation:

Given

there are six integers to win a lottery

case-1 Integer not exceeding 40

no of ways to choose 6 incorrect numbers

=\dfrac{^{34}C_{6}}{^{40}C_{6}}

=0.35

Case-2 no of ways to choose 6 incorrect numbers out of 48 integers

=\dfrac{^{42}C_{6}}{^{48}C_{6}}

=0.427

Case-3 no of ways to choose 6 incorrect numbers out of 56 integers

\dfrac{^{50}C_{6}}{^{56}C_{6}}

=0.489

Cae-4 no of ways to choose 6 incorrect numbers out of 64 integers

\dfrac{^{58}C_{6}}{^{64}C_{6}}

=0.54

6 0
3 years ago
Six less than 2 times “y” is 34 equation form
wel
2y-6=34 is the needed equation
8 0
3 years ago
Read 2 more answers
Find the area of the polygon. Figure ABCDE is shown. A is at 6, 0. B is at negative 4, 5. C is at 2, 5. D is at 2, 9. E is at 6,
kondaur [170]

This question is incomplete. The attached image was obtained online

Answer:

41 square units

Step-by-step explanation:

Looking at diagram that was attached, we can see that the Polygon s the combination of a square and a triangle.

In square CDEF we have:

The lengths of the side of the square= 4 units

Hence, the area of square is: length ²

Area of square= 4²

=16 square units

Also, in ΔBFA we have:

The base of the triangle is calculated as

=6 + 4= 10 units

height of the triangle is: FA= 5 units

The formula for Area of a triangle = 1/2 × Base × Height

Hence, we have area of ΔBFA as:

= 1/2 × 10 × 5

Area= 25 square units

The Area of the Polygon = Area of the square + Area of the triangle

16 square units + 25 square units

= 41 square units

7 0
3 years ago
Solve the quadratic function using square root X+10x+25 =18
lawyer [7]

Answer:

= − 7 /1 1  in fraction form

Step-by-step explanation:

STEP 1: Multiply by 1

1 + 1 0 + 2 5 = 1 8

+ 1 0 + 2 5 = 1 8                                                                                                                               STEP 2: Combine like terms

+ 1 0 + 2 5 = 1 8

1 1 + 2 5 = 1 8                                                                                                                       STEP 3: Subtract  2 5   from both sides of the equation

11x+25=18

1 1 + 2 5 − 2 5 = 1 8 − 2 5

STEP 4: Simplify  by subtracting the numbers

1 1 + 2 5 − 2 5 = 1 8 − 2 5

11x+25−25=18−25                                                                                                   1 1 = 1 8 − 2 5                                                                                                                                   1 1 =  -7

STEP 5: Divide both sides of the equation by the same term                                                     1 1 = − 7                                                                                                                         11x/ 11x = −7/ 1 1 (set up as a fraction)                                                                       STEP 6: Cancel terms that are in both the numerator and denominator

=  − 7 /1 1                                                                                                                      SOLUTION

=  − 7 /1 1

5 0
3 years ago
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