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Zepler [3.9K]
4 years ago
9

Select the statement where the value of the unknown number is 1.7

Mathematics
1 answer:
kherson [118]4 years ago
7 0
Lets say, unknown number = a = 1.7

A. a/1.7 = 0.1   ->  a = 0.17

B. 0.1/a = 1.7   ->  a = 0.05

C. a/17 = 0.1    -> a = 1.7

D. a/0.1 = 1.7   -> a = 0.17

The answer is C
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What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?
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x = \frac{ 5 \ + \ \sqrt{31}}{2} \ , \ x = \frac{ 5 \ - \ \sqrt{31}}{2}

Step-by-step explanation:

2x^2 - 10x - 3 = 0 \\\\a = 2 \ , b = - 10 \ , \ c =  - 3 \\\\x = \frac{-b^2\  \pm \ \sqrt{b^2 - 4ac}}{2a}\\\\x = \frac{10 \ \pm \sqrt{(-10)^2 - ( 4 \times 2 \times -3)} }{2 \times 2}\\\\x = \frac{10 \ \pm \sqrt{(100 - ( -24 )} }{4}\\\\x = \frac{10 \ \pm \sqrt{(100 + 24 } }{4}\\\\x = \frac{ 10 \ \pm \sqrt{124}}{4}\\\\x = \frac{ 10 \ \pm \sqrt{4 \times 31}}{4}\\\\x = \frac{ 10 \ \pm \sqrt{2^2 \times 31}}{4}\\\\x = \frac{ 10 \ \pm2 \sqrt{31}}{4}\\\\x = \frac{ 5 \ \pm\sqrt{31}}{2}\\\\

x = \frac{ 5 \ + \ \sqrt{31}}{2} \ , \ x = \frac{ 5 \ - \ \sqrt{31}}{2}

3 0
3 years ago
If $580 is invested in an account which earns 9% interest compounded annually, what will be the balance of the account at the en
joja [24]
The formula for compounded interest is A = P (1+r/n)^nt.
P=580 
r = .09
n = 1
t = 9
<span>
To find how much the balance is at the end of nine years, plug in all of the knows into the formula.</span>
A = 1259.698 is how much the balance will be. (Rounded to 1259.70 if you round to the nearest cent).



8 0
4 years ago
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