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sesenic [268]
2 years ago
14

Factor this polynomial completely x2 + 3x – 18 A. (x-2)(x + 9) B. (x+3)(x-6) оо C. (x - 3)(x+6) D. (x - 3)(x-6)​

Mathematics
2 answers:
Naya [18.7K]2 years ago
5 0

Answer:

x²+3x-18 = (x-3)(x+6)

Step-by-step explanation:

Polynomial: x²+3x-18

You can see that this is in the form of a quadratic equation, writing it in equation form we get: x²+3x-18 = 0

As this is a standard quadratic equation, we just need to find the two solutions and fill them in into the formula ax²+bx+c = (x-x₁)(x-x₂)

where x_{1} =\frac{-b+\sqrt{b^{2}-4ac } }{2a} and x_{2} =\frac{-b-\sqrt{b^{2}-4ac } }{2a}

(or the other way around, doesn't matter which one is x₁ and x₂)

Filling in the numbers (a=1, b=3, c=-18) we find that the equation has the following solutions:

x_{1} =\frac{-3+\sqrt{9+72}}{2}=\frac{-3+\sqrt{81}}{2}=\frac{-3+9}{2}=\frac{6}{2}=3

x_{2} =\frac{-3-\sqrt{9+72}}{2}=\frac{-3-\sqrt{81}}{2}=\frac{-3-9}{2}=\frac{-12}{2}=-6

This means that we can just fill them in into the formula ax²+bx+c = (x-x₁)(x-x₂):

We get that: x²+3x-18 = (x-3)(x+6)

Umnica [9.8K]2 years ago
3 0

Answer:

C. (x-3)(x+6)

Step-by-step explanation:

I think the equation meant x^2+3x-18?

Anyways, to factor these kinds of quadratic, keep into consideration:

ax^2+bx+c=(x+w)(x+v)

ONLY if:

w+v=b\\wv=c

Start off by finding factors of c, which in this case, -18:

±(1, 2, 3, 6, 9, 18)

If one of the numbers is negative then the other number must be positive.

Find which two factors will sum up to b, which in this case, is 3.

1+(-18)\neq 3\\2+(-9)\neq 3\\3+(-6)\neq 3\\6+(-3)=3\\9+(-2)\neq 3\\18+(-1)\neq 3\\

The only two factors that work are 6 and -3.

Replace them into the factored form:

(x+w)(x+v)\\(x+6)(x-3)\\(x-3)(x+6)

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Answer:

%82.5

Step-by-step explanation:

  1. The final exam of a particular class makes up 40% of the final grade
  2. Moe is failing the class with an average (arithmetic mean) of 45% just before taking the final exam.

From point 1 we know that Moe´s grade just before taking the final exam represents 60% of the final grade. Then, using the information in the point 2 we can compute Moe´s final grade as follows:

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6 0
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mylen [45]
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Another example: as x gets closer to x = 4 from the right hand side, the y value gets closer to y = 4. This y value is different if you approach x = 0 from the left side (y would approach y = 1/2)

Use examples like this and you'll get the results you see in "figure 1"

For any function values, you'll look for actual points on the graph. A point does not exist if there is an open circle. There is an open circle at x = 2 for instance, so that's why f(2) = UND. On the other hand, f(0) is defined and it is equal to 4 as the point (0,4) is on the function curve.

=======================================================

Problem 2

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y = - \frac{1}{2} x + 3 ← is in slope- intercept form

with slope m = - \frac{1}{2}

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