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Morgarella [4.7K]
3 years ago
5

X+9^4=[4234+56/23] x94 = ? pelase show work

Mathematics
1 answer:
Lana71 [14]3 years ago
3 0

Answer:

391,660.6

Step-by-step explanation:

First we need to do what is in the parentheses. 56/23 equals 2.4. 4234 + 2.4 is 4236.4...  4236.4 times 94 is 398,221.6... Now 9 to the fourth power is 6561. x + 6561 is 398,221.6 so x equals 391,660.6... I hope this helps and please make me the brainliest. Thanks!

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Sever21 [200]

Answer:

The first answer is 1/3 the second answer is also 1/3

Step-by-step explanation:

If you count the number of names there are and take two out that would round down from 2/6 to 1/3. The answer is the same for both questions.

4 0
3 years ago
Solve for n. 11(n – 1) + 35 = 3n n = –6 n = –3 n = 3 n = 6
alisha [4.7K]

Answer:

n = 6

you just use pemdas

6 0
3 years ago
After solving an equation, you end up with integers on both sides of the equation. What can you interpret about the equation are
murzikaleks [220]

Answer:

The equation is:

An identity

Has infinitely many solutions

No solution

Step-by-step explanation:

Because there is integers on both sides, we know that any attempts to fix this will either cause an identity, or a false numerical equation(an identity but <em>w r o n g</em>).(Note, an identity can either mean 2 = 2 or x = x).

Identities have infinite solutions, because it does not matter what you put in, the equation will always be true. False equations do not have a solution because they aren't even true equations.

Hope this helps!

5 0
4 years ago
Find the equation of a line that is perpendicular to y = 3x – 5 and passes through the point (1, -3).
Svetradugi [14.3K]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad y = \stackrel{\stackrel{m}{\downarrow }}{3}x-5

well then therefore

\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}

so we're really looking for the equation of a line with slope of -1/3 and that passes through (1, -3 )

(\stackrel{x_1}{1}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-\cfrac{1}{3}}(x-\stackrel{x_1}{1})\implies y+3=-\cfrac{1}{3}x+\cfrac{1}{3} \\\\\\ y=-\cfrac{1}{3}x+\cfrac{1}{3}-3\implies y=-\cfrac{1}{3}x-\cfrac{8}{3}

6 0
2 years ago
3x + 2y = 7
Lady bird [3.3K]
It would be the last option, (5, -4)
4 0
2 years ago
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