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zhannawk [14.2K]
3 years ago
11

What graph equation is parallel to the graph 8x - 2y = 30?

Mathematics
2 answers:
kiruha [24]3 years ago
7 0

Answer:

Any graph with the same slope but with different y intercepts is parallel to that. For example in y = mx + b form the equation will be

y = 4x - 15

So, some equations that will be parallel

y = 4x

y = 4x - 16

y = 4x +3

Hoped this helped ya :)

Elina [12.6K]3 years ago
4 0

Answer:

y=4x-5

Step-by-step explanation:

First step is to turn the given equation into slope intercept form y=mx+b.

The goal is to isolate y: first subtract 8x from both sides and to completely simplify the equation divide by -2 on both sides:

8x-2y=30

-2y=-8x+30

y= -8/-2x + 30/-2

y=4x-15

** when adding a negative, it's the same as subtracting, so I just changed it

Now you have your equation, we want to focus on the slope. If two equations have the same slope, they won't ever intersect bc they grow at the the same rate.

Use this equation: y=4x+b and bc you're trying to find the equation of another line, pick an ordered pair (it doesn't matter what it is) and plug it into x and y to solve for b (the y-intercept) in order to fulfill y=mx+b

I'm using (2,3):

3=4(2)+b

3=8+b

-5=b

Now you have b, plug it back into y=4x+b (omit the coordinates you put in) and you'll get:

y=4x-5 as your answer

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In an arithmetic sequence, t4 + t5 + t6 = 300, and t15 +t16+ t17 = 201. Find t18.
stiks02 [169]
In an arithmetic sequence:
Tn=t₁+(n-1)d

t₄=t₁+(4-1)d=t₁+3d
t₅=t₁+(5-1)d=t₁+4d
t₆=t₁+(6-1)d=t₁+5d

t₄+t₅+t₆=(t₁+3d) +(t₁+4d)+(t₁+5d)=3t₁+12d

Therefore:
3t₁+12d=300    (1)


t₁₅=t₁+(15-1)d=t₁+14d
t₁₆=t₁+(16-1)d=t₁+15d
t₁₇=t₁+(17-1)d=t₁+16d

t₁₅+t₁₆+t₁₇=(t₁+14d)+(t₁+15d)+(t₁+16d)=3t₁+45d

Therefore:
3t₁+45d=201    (2)

With the equations (1) and (2) we make an system of equations:

3t₁+12d=300
3t₁+45d=201

we can solve this system of equations by reduction method.

  3t₁+12d=300
-(3t₁+45d=201)
-----------------------------
       -33d=99      ⇒d=99/-33=-3

3t₁+12d=300
3t₁+12(-3)=300
3t₁-36=300
3t₁=300+36
3t₁=336
t₁=336/3
t₁=112

Threfore:

Tn=112+(n-1)(-3)
Tn=112-3n+3
Tn=115-3n

Now, we calculate T₁₈:

T₁₈=115-3(18)=115-54=61

Answer: T₁₈=61




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