Is the square root of 9 a real number
1 answer:
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The correct answer is: [B]: " 22 " .
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Explanation:
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Given:
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;
Solve when: "n = 3" ;
Rewrite the expression; substituting "3" for all values of "n" ; as follows:
→
;
The "6" cancels out to "2" ; & the "3" cancels out to "1" ;
→ {since: " {6 ÷ 3 = 2}" ; and since: " {2 ÷ 2 = 1}" .
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→ Since the "denominator" is "1" ; and any value, divided by "1"; results in that original value; we can eliminate the denominator.
→ Now, we can rewrite the expression as:
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→ " 2(3² + 2)" ;
= 2(9 + 2) ;
= 2(11) ;
= " 22 " .
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→ The answer is: " 22 " ; which is: Answer choice: [B]: " 22 " .
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Explanation:
_________________________________________________________
Given:
_________________________________________________________
Solve when: "n = 3" ;
Rewrite the expression; substituting "3" for all values of "n" ; as follows:
→
The "6" cancels out to "2" ; & the "3" cancels out to "1" ;
→ {since: " {6 ÷ 3 = 2}" ; and since: " {2 ÷ 2 = 1}" .
_________________________________________________________
→ Since the "denominator" is "1" ; and any value, divided by "1"; results in that original value; we can eliminate the denominator.
→ Now, we can rewrite the expression as:
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→ " 2(3² + 2)" ;
= 2(9 + 2) ;
= 2(11) ;
= " 22 " .
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→ The answer is: " 22 " ; which is: Answer choice: [B]: " 22 " .
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