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oksian1 [2.3K]
2 years ago
7

A number is equal to 3 times a smaller number. Also, the sum of the smaller number and 4 is the larger number. The situation is

graphed on the coordinate plane below, where x represents the smaller number and y represents the larger number.
Which two equations represent the situation?
Mathematics
1 answer:
Juli2301 [7.4K]2 years ago
7 0
1. You have that:

 - <span> "x" represents the smaller number and "y" represents the larger number. 
 - </span><span>A number is equal to 3 times a smaller number: y=3x
 - </span><span> The sum of the smaller number and 4 is the larger number: y=x+4

 2. Therefore, you have the following system of equations:

 y=3x   (i)
 y=x+4   (ii)

 3. When you solve it, you obtain:

 3x=x+4
 3x-x=4
 2x=4
 x=2

 y=3x
 y=(3)(2)
 y=6

 4. </span><span>Which two equations represent the situation? The answer is:
</span>
 y=3x 

 y=x+4   
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270
Step-by-step explanation:
Area = length × width
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2 years ago
Provide me three coordinate points for the following, given the Slope and Y-intercept. 5. Slope = 7/9, Y intercept = 12(give me
madam [21]

Since we have that the slope is m = 7/9 and the y-intercept is b = 12, we can write the equation of the line in slope-intercept form:

\begin{gathered} y=mx+b \\ \Rightarrow y=\frac{7}{9}x+12 \end{gathered}

to find three coordinate points, we can use arbitrary values on x to get the y-coordinate. To make things easier, let's use x = 9, 18 and 27:

\begin{gathered} x=9 \\ \Rightarrow y=\frac{7}{9}(9)+12=7+12=19 \\ x=18 \\ \Rightarrow y=\frac{7}{9}(18)+12=7(2)+12=14+12=26 \\ x=27 \\ \Rightarrow y=\frac{7}{9}(27)+12=7(3)+12=21+12=33 \end{gathered}

therefore, the line with slope m = 7/9 and y-intercept 12 passes through the three points (9,19), (18,26) and (27,33)

8 0
1 year ago
Help me solve this please. I don't know the formula for this.​
den301095 [7]

Answer

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Step-by-step explanation:

base(x)

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8 0
3 years ago
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an
maxonik [38]

Answer:

5.0 ft-lbf

Step-by-step explanation:

The force is

F = \dfrac{9}{6^x}

This force is not a constant force. For a non-constant force, the work done, <em>W</em>, is

W = \int\limits^{x_2}_{x_1} {F(x)} \, dx

with x_1 and x_2 the initial and final displacements respectively.

From the question, x_1  =0 and x_2 = 12.

Then

W = \int\limits^{12}_0 {\dfrac{9}{6^x}} \, dx

Evaluating the indefinite integral,

\int\limits \dfrac{9}{6^x} \, dx  =9 \int\limits\!\left(\frac{1}{6}\right)^x \, dx

From the rules of integration,

\int\limits a^x\, dx = \dfrac{a^x}{\ln a}

9 \int\limits \left(\frac{1}{6}\right)^x \, dx = 9\times\dfrac{(1/6)^x}{\ln(1/6)} = -5.0229\left(\dfrac{1}{6}\right)^x

Returning the limits,

\left.-5.0229\left(\dfrac{1}{6}\right)^x\right|^{12}_0 = -5.0229(0.1667^{12} - 0.1667^0) = 5.0229 \approx 5.0 \text{ ft-lbf}

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3 years ago
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elena55 [62]

Answer:

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Step-by-step explanation:

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