3 years ago

-6w^7(-4w^2) simplify

Mathematics

2 answers:

Veseljchak [2.6K]3 years ago

3 0

Answer:

24w⁹

Step-by-step explanation:

Galina-37 [17]3 years ago

3 0

Answer:

the answer is 24w⁹ :)

Step-by-step explanation:

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The area of a rectangular playground enclosure at francis lewis hw is 500 square meters. the lenght of the playground is 5 meter

Alex Ar [27]

A=L*W
L=W+5
A=(W+5)W
500=W²+5W
W²+5W-500=0

W=(-5+/-√(25+4*500))/2=(-5+/-√2025)/2=(-5+/-45)/2
we are going to take only positive value, so W=(-5+45)/2=20
L=W+5=20+5=25
W=20,
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Can you guys help me out on this? I'm still learning sign, cosign, and tangent :)

Yakvenalex [24]

Answer:

$\sin d = \frac{4}{7}$ ; $\sin e = \frac{\sqrt{33} }{7}$

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Step-by-step explanation:

For a right angled triangle with one of its angle α (alpha) :-

$\sin \alpha = \frac{Side \: opposite \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}$

$\cos \alpha = \frac{Side \: adjacent \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}$

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According to the question ,

1) When α (alpha) = d

$\sin d = \frac{4}{7}$

$\cos d = \frac{\sqrt{33} }{7}$

$\tan d = \frac{4}{\sqrt{33} }$

2) When α (alpha) = e

$\sin e = \frac{\sqrt{33} }{7}$

$\cos e = \frac{4}{7}$

$\tan e = \frac{\sqrt{33} }{4}$

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marusya05 [52]

10.5+(-6.1) Hope this helps

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4 years ago

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