Question

Can you guys help me out on this? I'm still learning sign, cosign, and tangent :)

Answer 1

Answer:

$\sin d = \frac{4}{7}$ ; $\sin e = \frac{\sqrt{33} }{7}$

$\cos d = \frac{\sqrt{33} }{7}$ ; $\cos e = \frac{4}{7}$

$\tan d = \frac{4}{\sqrt{33} }$ ; $\tan e = \frac{\sqrt{33} }{4}$

Step-by-step explanation:

For a right angled triangle with one of its angle α (alpha) :-

• $\sin \alpha = \frac{Side \: opposite \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}$

• $\cos \alpha = \frac{Side \: adjacent \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}$

• $\tan \alpha = \frac{Side \: opposite \: to \: \alpha }{Side \: adjacent \: to \: \alpha }$

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According to the question ,

1) When α (alpha) = d

• $\sin d = \frac{4}{7}$

• $\cos d = \frac{\sqrt{33} }{7}$

• $\tan d = \frac{4}{\sqrt{33} }$

2) When α (alpha) = e

• $\sin e = \frac{\sqrt{33} }{7}$

• $\cos e = \frac{4}{7}$

• $\tan e = \frac{\sqrt{33} }{4}$