Answer:
a) 2.5 shots
b) 59.4 shots
c) 4.87 shots
Step-by-step explanation:
Probability of making the shot = 0.6
Probability of missing the shot = 0.4
a) The expected number of shots until the player misses is given by:
![E(X) = \frac{1}{P(X)}=\frac{1}{0.4} \\E(X) = 2.5\ shots](https://tex.z-dn.net/?f=E%28X%29%20%3D%20%5Cfrac%7B1%7D%7BP%28X%29%7D%3D%5Cfrac%7B1%7D%7B0.4%7D%20%20%5C%5CE%28X%29%20%3D%202.5%5C%20shots)
The expected number of shots until the first miss is 2.5
b) The expected number of shots made in 99 attempts is:
![E=99*0.6\\E=59.4\ shots](https://tex.z-dn.net/?f=E%3D99%2A0.6%5C%5CE%3D59.4%5C%20shots)
He is expected to make 59.4 shots
c) Let "p" be the proportion shots that the player make, the standard deviation for n = 99 shots is:
![s=\sqrt{n*p*(1-p)}\\ s= 4.87\ shots](https://tex.z-dn.net/?f=s%3D%5Csqrt%7Bn%2Ap%2A%281-p%29%7D%5C%5C%20s%3D%204.87%5C%20shots)
The standard deviation is 4.87 shots.
<span>Break down every term into prime factors. ...Look for factors that appear in every single term to determine the GCF. ...Factor the GCF out from every term in front of parentheses, and leave the remnants inside the parentheses. ...<span>Multiply out to simplify each term. thats it
</span></span>
Answer:
2
Step-by-step explanation:
4x+3=x+9
4x-x=9-3
3x=6
x=6/3
x=2
Answer:
the answer is A
Step-by-step explanation:
If you simplify 6/18 you get 1/3
Its the same with 3/9 because if you simplify that you also get 1/3