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sattari [20]
3 years ago
11

For what values of a is the distance between P(a,3) and Q(5,2a) greater than √26

Mathematics
1 answer:
Novay_Z [31]3 years ago
6 0
P(a,3)\ \ \ Q(5,2a)\\\\ PQ=\sqrt{(x_Q-x_P)^2+(y_Q-y_P)^2}\\\\ PQ>\sqrt{26}\\\\\sqrt{(5-a)^2+(2a-3)^2}>\sqrt{26}\\\\\sqrt{25-10a+a^2+4a^2-12a+9}>\sqrt{26}\\\\\sqrt{5a^2-22a+34}>\sqrt{26}\ \ |^{2}\\\\
5a^2-22a+34=26\ \ \ |Subtract\ 26\\\\
5a^2-22a+8=0\ \ \ |Factoring\\\\(a-4)(5a-2)=0\\\\
a=4\ \  or\ \  5a=2\\
a=4\ \ or\ \ a=\frac{2}{5}
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Step-by-step explanation:

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