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Tema [17]
3 years ago
9

Can I PLEASE get some help?

Mathematics
2 answers:
Leviafan [203]3 years ago
4 0
Well 1/40 is 0.025 so that should be the write fraction to use
erica [24]3 years ago
3 0
Step 1: 0.025 = 25/1000
Step 2: Simplify. 25/1000 = 1/40
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How do you write 309,099,990 in expanded form
Liono4ka [1.6K]
300,000,000+9,000,000+90,000+9,000+900+90
8 0
3 years ago
Simplify the rational expression. State any restrictions on the variable.
ExtremeBDS [4]

we are given

\frac{(n^4-10n^2+24)}{(n^4-9n^2+18)}

Firstly, we will factor numerators and denominators

\frac{(n^4-10n^2+24)}{(n^4-9n^2+18)}=\frac{(n^2-6)(n^2-4)}{(n^2-3)(n^2-6)}

we can see that

n^2 -6 is factor on both numerator and denominator

so, it will get cancelled

and n^2 -6 can not be equal to 0

so, one of restriction is

n^2-6\neq 0

n\neq -+ \sqrt{6}

we can simplify it

\frac{(n^4-10n^2+24)}{(n^4-9n^2+18)}=\frac{(n^2-4)}{(n^2-3)}

we know that denominator can not be zero

n^2-3\neq 0

n\neq -+ \sqrt{3}

so, option-B.......Answer

3 0
3 years ago
Please help me with this question
ddd [48]

\qquad\qquad\huge\underline{{\sf Answer}}♨

Let's solve ~

Total Mini - Easter eggs = 1345

Number of students = 26

So, let's find how many eggs will each student get through division ~

\qquad \tt  \dashrightarrow \: \dfrac{1345}{26}  = 51 +remainder= 19

So, each student will get 51 mini - Easter egg each.

And there would be 19 remaining eggs in there ~

4 0
2 years ago
Does anyone know how to solve this?
Bezzdna [24]

Use this version of the Law of Cosines to find side b:

b^2 = a^2 + c^2 − 2ac cos(B)

We want side b.

b^2 = (41)^2 + (20)^2 - 2(41)(20)cos(36°)

After finding b, you can use the Law of Sines to find angles A and C or use other forms of the Law of Cosines to find angles A and C.

Try it....

6 0
4 years ago
Find all solutions for the equation. x^2 +4x -8 =0​
siniylev [52]

Answer:20

Step-by-step explanation:

7 0
3 years ago
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