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3 years ago

Which of the following numbers is between 2/5 and 7/8???

Mathematics

2 answers:

mars1129 [50]3 years ago

7 0

The answer is 3/4 use a calculator if you want to check!

kondaur [170]3 years ago

6 0

Th answer is 3/4 I’m pretty sure

You might be interested in

5x + 4m = 43my + 6 solve for m

pav-90 [236]

9514 1404 393

Answer:

m = (5x -6)/(43y -4)

Step-by-step explanation:

Subtract 4m+6 to separate m-terms from other terms.

5x +4m -(4m +6) = 43my +6 -(4m +6)

5x -6 = 43my -4m

5x -6 = m(43y -4) . . . . factor out m

(5x -6)/(43y -4) = m . . . . divide by the coefficient of m

7 0

3 years ago

How to solve X + y = 2<br> X - y = 4

SpyIntel [72]

So y+x=2
x-y=4
one way is subsituteion where yousubisutte one of the number for another exg

x-y=4
add y to both sides
x=y+4
subsitute y+4 for x in x+y=2
y+4+y=2
2y+4=2
subtract 4 from both sides
2y=-2
divide both sides by 2
y=-1
subsiutte
x+y=2
x-1=2
x=3

or elimination

x+y=2
x-y=4
add the two equations and cancel the y terms

x+x+y-y=2+4
2x=6
divide both sides by 2
x==3
subsitute
x+y=2
3+y=2
y=-1

so x=3
y=-1

5 0

3 years ago

determine whether the lines intersect and if so find the point of intersection and the cosine of the angle of intersection x=4t+

Fittoniya [83]

Answer:

As the lines are not intersecting nor parallel, they must be skew.

Step-by-step explanation:

Question is incomplete, we consider the nearest match available online.

Parametric equations of two lines are:

L₁ : x=4t+2 , y = 3 , z =-t+1

L₂: x=2s+2 , y= 2s+5 , z = s+1

If lines are parallel then parametric coordinates must be equal scalar multiple of each other which s not true here.

$4t+2=2s+2 ---(1)\\ \\3=2s+5---(2) \\\\-t+1=s+1---(3)$

If lines are intersecting then parametric coordinates must be equal for some value of t and s.

$From (3)\\-t=s\\From (2)\\\\s=\frac{3-5}{2}\\\\s=-1\\\implies t=1\\\\To\,\,check\,\, the \,\,values \,\,of \,\,s\,\, and \,\,t \,\,for\,\,intersection\,\,put \,\,them\,\, in\,\, (1)\\\\4(1)+2= 2(-1)+2\\ 6\ne0$

Hence the lines are not intersecting nor parallel, they must be skew.

6 0

3 years ago

Find the area of the shaded region. Round the nearest hundredth if necessary. YZ=14.2m

andreyandreev [35.5K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

$A_1 = 67.58 \ in^2$

$A_2 =415.4 \ ft^2$

$A_3 = 8.48 \ cm^2$

$A_4 = 480.38 \ m^2$

Step-by-step explanation:

Generally the area of a sector is mathematically represented as

$A = \frac{\theta}{360} * \pi r^2$

Now at $r_1 = 11 in$ and $\theta_1 = 64^o$

$A_1 = \frac{64}{360} * 3.142 * 11^2$

$A_1 = 67.58 \ in^2$

Now at $r_2 = 20 ft$ in and $\theta_2 = 119 ^o$

$A_2 = \frac{119}{360} * 3.142 * 20^2$

$A_2 =415.4 \ ft^2$

Now at $r_3 = 6.5 cm$ and $\theta_3 = 23 ^o$

$A_3 = \frac{23}{360} * 3.142 * 6.5 ^2$

$A_3 = 8.48 \ cm^2$

Now at $r_4 = 14.2 m$ and $\theta_4 = 360 -87 = 273 ^o$

$A_4 = \frac{273}{360} * 3.142 * 14.2^2$

$A_4 = 480.38 \ m^2$

6 0

3 years ago

How would I solve this Rational Equation? <br><br>Solve for all values of x.

Nesterboy [21]

9514 1404 393

Answer:

x = 4

Step-by-step explanation:

I like to put these in the form f(x) = 0. We can do that by subtracting the right side. Common factors can be cancelled from numerator and denominator, provided they are not zero.

$\dfrac{7}{x+3}+\dfrac{3}{x-3}-\dfrac{x}{x-3}=0\\\\ \dfrac{7(x-3)+(x+3)(3-x)}{(x+3)(x-3)}=0\\\\\dfrac{(x-3)(4-x)}{(x-3)(x+3)}=0\\\\ \dfrac{4-x}{x+3}=0\qquad x\ne3\\\\x=4 \qquad\text{equate the numerator to zero, add $x$}$

_____

If you leave the numerator as (x-3)(4-x), then there are two values of x that make it zero. Because x=3 makes the equation "undefined", it cannot be considered to be a solution.

4 0

3 years ago

Which of the following numbers is between 2/5 and 7/8??? ​​

Which of the following numbers is between 2/5 and 7/8???