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Alex
3 years ago
10

Is 5.75 irrational or rational

Mathematics
2 answers:
LUCKY_DIMON [66]3 years ago
5 0
Rational. irrational numbers are numbers that never end.
Zanzabum3 years ago
4 0

Answer:

Rational number

Step-by-step explanation:

We are given that a number 5.75

We have to find that given number is rational or irrational

Rational number : It is that number which can be written as \frac{p}{q}

Where q is not equal to zero and p, q are integers.

Irrational number : It is that number which is not rational .If a number is not rational then the number is called irrational number .

{5.75}=\frac{575}{100}=\frac{23}{4}

When we remove decimal then we write 100 in the denominator because there are  two digits after decimal.

The given number is of the from \frac{p}{q} and 23 and 4 are both integers.

Hence, the number is rational number .

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5<b-3. whats the answer????
9966 [12]

Answer:

5<b-3

Add 3 on both sides

8<b

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b>8

Hope I helped!

8 0
3 years ago
Read 2 more answers
A manager records the number of hours, X, each employee works on his or her shift and develops the probability distribution belo
Reika [66]

Answer:

c. 2

Step-by-step explanation:

Given : X = No. of hours worked

           No. of people work for the manager = 50

           X = 3, 4 , 5 , 6 , 7, 8

           P(X) = 0.1 , ? , 0.14 , 0.3 , 0.36 , 0.06

To Find : No. of people work for four hours

Solution : First understand the fact that sum of all probabilities is equal to 1

So, sum of all values of P(X) = 1

⇒0.1+?+0.14+0.3+0.36+0.06 = 1

⇒0.96+? = 1

⇒?= 1-0.96

⇒? = 0.04

So, the probability of no. of people worked for 4 hours is 0.04.

⇒P(4)=0.04

Thus , To calculate no. of people work for four hours :

0.04\times 50

⇒ 2 no. of people work for four hours per shift .


5 0
3 years ago
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Find the two numbers that have a<br> difference of 3 and a sum of 27.
polet [3.4K]
12 and 15 

15-12=3
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2 years ago
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2 years ago
Please help me answer this question.
iVinArrow [24]
4 6/9 + 7/9 = 5 3/9
Hope this helps
Answer:
5 3/9 or 5 1/3
3 0
1 year ago
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