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zvonat [6]
3 years ago
15

What is the equation of the following line written in slope-intercept form?​

Mathematics
1 answer:
Svetllana [295]3 years ago
4 0

Answer:

y = 5x

Step-by-step explanation:

Line equation is given as y = mx + b

Where, m is the slope of the line, which is,

m = \frac{y2 - y1}{x2 - x1}

b is the y-intercept. It is the point at which the line crosses the y-axis for which the value of x = 0.

=>Find m and b to derive an equation for the line.

using the 2 coordinate pairs, (1, 5), (-1, -5),

Let, x2 = -1,

x1 = 1,

y2 = -5,

y1 = 5

m = \frac{y2 - y1}{x2 - x1}

m = \frac{-5 - 5}{-1 - 1}

m = \frac{-10}{-2}

m = 5

From the graph given, the line intercepts the y-axis at point 0. Therefore b = 0.

Plug in the values of m and b in the line of equation.

y = mx + b

y = 5x + 0

y = 5x

Therefore, the equation of the line, in the graph above, written in slope-intercept form is:

y = 5x

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