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madam [21]
3 years ago
5

A sprinter can accelerate with constant acceleration for 4.00 s before reaching top speed. He can run the 100 m dash in 10 s. Wh

at is his speed as he crosses the finish line?
Physics
1 answer:
OLEGan [10]3 years ago
7 0

Answer:

12.5 m/s

Explanation:

If the avg speed is 10 m/s we assume that the speed is constant and not fluctuating

If VT (Velocity*Time) is equal to speed at the end of the 4 seconds of accel. it is the top speed at the finish line

since the speed is 0 at the beginning of races, we will use V0= 0 m/s

So the avg velocity for those 4 seconds is (VT+V0) /2 = or 1/2 VT (for 40% of the race)

The avg velocity for the last 6 seconds is, of course, VT (for 60% of the race

hence

(1/2VT)(.4) + VT(.6) = 10 m/s

VT = 10/.8 = <u>12.5 m/s </u>

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Vlada [557]

Answer:

The required angular speed the neutron star is 10992.32 rad/s

Explanation:

Given the data in the question;

mass of the sun M_S = 1.99 × 10³⁰ kg

Mass of the neutron star

M_N = 2( M_S )

M_N = 2( 1.99 × 10³⁰ kg )

M_N = ( 3.98 × 10³⁰ kg )

Radius of neutron star R_N = 13.0 km = 13 × 10³ m

Now, let mass of a small object on the neutron star be m

angular speed be ω_N.

During rotational motion, the gravitational force on the object supplies the necessary centripetal force.

GmM_N = / R_N² = mR_Nω_N²

ω_N² = GM_N = / R_N³

ω_N = √(GM_N = / R_N³)

we know that gravitational G = 6.67 × 10⁻¹¹ Nm²/kg²

we substitute

ω_N = √( (  6.67 × 10⁻¹¹ )( 3.98 × 10³⁰ ) ) / (13 × 10³ )³)

ω_N = √( 2.65466 × 10²⁰ / 2.197 × 10¹²

ω_N = √ 120831133.3636777

ω_N = 10992.32 rad/s

Therefore, The required angular speed the neutron star is 10992.32 rad/s

5 0
3 years ago
QUESTION 2 DOK 3 A Thompson's gazelle has a maximum acceleration of 4.5 m/s2 At this acceleration, how much time is required for
Dominik [7]

Answer:

2.47 s

Explanation:

Convert the final velocity to m/s.

  • 40 km/h → 11.1111 m/s

We have the acceleration of the gazelle, 4.5 m/s².

We can assume the gazelle starts at an initial velocity of 0 m/s in order to determine how much time it requires to reach a final velocity of 11.1111 m/s.

We want to find the time t.

Find the constant acceleration equation that contains all four of these variables.

  • v = v₀ + at

Substitute the known values into the equation.

  • 11.1111 = 0 + (4.5)t
  • 11.1111 = 4.5t
  • t = 2.469133333

The Thompson's gazelle requires a time of 2.47 s to reach a speed of 40 km/h (11.1111 m/s).

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Harlamova29_29 [7]

Answer:

4, 56

Explanation:

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