Neutron stars are extremely dense objects that are formed from the remnants of supernova explosions. Many rotate very rapidly. S
1 answer:
Answer:
The required angular speed the neutron star is 10992.32 rad/s
Explanation:
Given the data in the question;
mass of the sun M = 1.99 × 10³⁰ kg
Mass of the neutron star
M = 2( M
)
M = 2( 1.99 × 10³⁰ kg )
M = ( 3.98 × 10³⁰ kg )
Radius of neutron star R = 13.0 km = 13 × 10³ m
Now, let mass of a small object on the neutron star be m
angular speed be ω.
During rotational motion, the gravitational force on the object supplies the necessary centripetal force.
GmM = / R
² = mR
ω
²
ω² = GM
= / R
³
ω = √(GM
= / R
³)
we know that gravitational G = 6.67 × 10⁻¹¹ Nm²/kg²
we substitute
ω = √( ( 6.67 × 10⁻¹¹ )( 3.98 × 10³⁰ ) ) / (13 × 10³ )³)
ω = √( 2.65466 × 10²⁰ / 2.197 × 10¹²
ω = √ 120831133.3636777
ω = 10992.32 rad/s
Therefore, The required angular speed the neutron star is 10992.32 rad/s
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Answer:
The force on one square foot of the earth’s surface caused by the atmosphere is 101.4 kN.
Explanation:
To force is given by:
(1)
Where:
P: is the pressure = 14.7 lb/in²
A: is the area = 1 m²
By entering the above values into equation (1) we have:
Therefore, the force on one square foot of the earth’s surface caused by the atmosphere is 101.4 kN.
I hope it helps you!
a) de Broglie wavelength of a 4-MeV proton: 14.3 fm
b) de Broglie wavelength of a 40-GeV electron: 0.031 fm
Explanation:
a)
The de Broglie wavelength of an object is given by
(1)
where
h is the Planck constant
p is the momentum of the particle
Here we want to find the de Broglie wavelength of a 4-MeV proton. The rest of mass of the proton in MeV is
And since , this means that the proton is non-relativistic. So its kinetic energy is related to its momentum by
which means
where
is the kinetic energy
is the proton mass
Substituting, we find
b)
In this case, the electron has kinetic energy of 40 GeV, while the rest mass of an electron is
Since , the electron is ultra-relativistic: so we can rewrite its energy as
The equation (1) can also be rewritten as
where c is the speed of light. The quantity at the denominator is the energy, so
where:
is the energy of the electron
And substituting, we find:
Learn more about de Broglie wavelength:
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