Answer:
Yes, the function satisfies the hypothesis of the Mean Value Theorem on the interval [1,5]
Step-by-step explanation:
We are given that a function

Interval [1,5]
The given function is defined on this interval.
Hypothesis of Mean Value Theorem:
(1) Function is continuous on interval [a,b]
(2)Function is defined on interval (a,b)
From the graph we can see that
The function is continuous on [1,5] and differentiable at(1,5).
Hence, the function satisfies the hypothesis of the Mean Value Theorem.
Answer: (4,8) which is choice A
f = 2/3 is the scale factor
x = 6 and y = 12 pair up to get the coordinates for point K's location
multiply f by x and y to get the new location
f*x = (2/3)*6 = (2/3)*(6/1) = (2*6)/(3*1) = 12/3 = 4
f*y = (2/3)*12 = (2/3)*(12/1) = (2*12)/(3*1) = 24/3 = 8
The results we get are 4 and 8. So (6,12) moves to (4,8)
This scale factor 2/3 = 0.667 is less than 1, so the image is smaller compared to the pre-image.