Answer:
1.we know the perimeter of the triangle=x-3+x+6+x=3x+3
so,answer is (b)3x+3
2.area of the triangle=1/2*b*h
=1/2*x+2*2x+6=x+2*2x+6/2=2x^2+6x+4x+12/2=2x^2+10x+12/2=2(x^2+5x+6)/2=x^2+5x+6
so,answer is(b)x^2+5x+6
Answer:
Pretty sure the first one is correct :)
Step-by-step explanation:
I hope this helps!
Answer:
x = 6
Step-by-step explanation:
Find the equation of the line
y = mx + b
Use the slope given 3 and the x of 4 and the y of 11 from the point given (4,11)
11 = 3(4) +b Solve for y
11 = 12 + b Subtract 12 from both sides
-1 = b
y = 3x -1 This is the equation of the line. Substitute in 17 for y and solve for x
17 = 3x -1 Add 1 to both sides
18 = 3x Divide both sides by 3
6 = x
Answer:
point C (-1, -3)
Step-by-step explanation:
The line you are looking for already has two givens: m = 2 and it has coordinate (2,3) on it. You can plug these in to find the equation of the line and then see which of the 4 points it must pass through.
3 = 2(2) + b
-1 = b
the line you are looking for is y = 2x - 1
First, you can rule out points D and B, because after a quick look, you can see that a line with a slope of 2 wouldn't come close to the point (2,3). Now you can choose between C (-1, -3) and A (-2, -3).
Now you can plug in the points C and A into the equation of the line that was obtained in the first part of this answer.
checking point A: -3 = 2(-2) - 1
-3= -5
not true, so now we check point C
checking point C: -3 = 2(-1) - 1
-3 = -2 - 1
-3 = -3
true, so the point must be C
