Let's say that in the beginning he weighted x and at the end he weighted x-y, y being the number of kg he wanted to loose.
first month he lost
y/3
then he lost:
(y-y/3)/3
this is
(2/3y)/3=2/9y
explanation: ((y-y/3) is what he still needed to loose: y minus what he lost already
and then he lost
(y-2/9y-1/3y)/3+3 (the +3 is his additional 3 pounts)
(y-2/9y-1/3y)/3-3=(7/9y-3/9y)/3+3=4/27y+3
it's not just y/3 because each month he lost one third of what the needed to loose at the current time, not in totatl
and the weight at the end of the 3 months was still x-y+3, 3 pounds over his goal weight!
so: x -y/3-2/9y-4/27y-3=x-y+3
we can subtract x from both sides:
-y/3-2/9y-4/27y-3=-y+3
add everything up:
-19/27y=-y+6
which means
-19/27y=-y+6
y-6=19/27y
8/27y=6
4/27y=3
y=20.25
so... that's how much he wanted to loose, but he lost 3 less than that, so 23.25
ps. i hope I didn't make a mistake in counting, let me know if i did. In any case you know HOW to solve it now, try to do the calculations yourself to see if they're correct!
Answer:
x=1
Step-by-step explanation:
where
.
By continuity of
, you have
As
in the numerator, you approach
; in the denominator, you approach
. So you have an indeterminate form
. Provided the limit indeed exists, L'Hopital's rule can be used.
Now the numerator approaches
, while the denominator approaches
, suggesting the limit above is 2. This means
Answer:
six hundred = 600
<u><em>Please mark as brainliest if answer is right </em></u>
Have a great day, be safe and healthy
Thank u
XD
Answer: <em>D. Yes, because it touches the y-axis exactly one time.</em>
Step-by-step explanation:
on the graph it shows that it touches -2y and almost touches 1x so there for it is D.
