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Assoli18 [71]
3 years ago
11

Simplify: 10 m: 20 m : 0.02 km

Mathematics
1 answer:
Arisa [49]3 years ago
4 0
Hope I’m right and hope it helps too

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What is <br><img src="https://tex.z-dn.net/?f=f%284%29%20%3D%20%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20%7D%20%20-%205" id="TexFormul
dexar [7]
<h3>Solution:</h3>

f(x) =  \sqrt{ {x}^{2} }  - 5 \\  =  > f(4) =  \sqrt{ {(4)}^{2} } - 5 \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  =  \sqrt{16 }   - 5 \\  =  4 - 5 \\  =  - 1 \\ or \\  =  - 4 - 5 \\  =  - 9

<h3>Answer:</h3>

-1 or -9

<h3>Hope it helps</h3>

ray4918 here to help

3 0
3 years ago
A student takes English and American History this semester. The probability that a student passes English is 0.5. The probabilit
mash [69]

Answer:

50% chance of passing english

40% chance of passing American History

30% chance of passing both classes

Step-by-step explanation:

3 0
2 years ago
In 3-6 write each decimal as a fraction
Paladinen [302]

Answer: 0.03 and - 0.06


Step-by-step explanation:


7 0
3 years ago
Two boats leave a dock at the same time. One boat travels south at 32 mi divided by hr32 mi/hr and the other travels east at 60
TEA [102]

Answer: the rate at which the distance between the boats is​ increasing is 68 mph

Step-by-step explanation:

The direction of movement of both boats forms a right angle triangle. The distance travelled due south and due east by both boats represents the legs of the triangle. Their distance apart after t hours represents the hypotenuse of the right angle triangle.

Let x represent the length the shorter leg(south) of the right angle triangle.

Let y represent the length the longer leg(east) of the right angle triangle.

Let z represent the hypotenuse.

Applying Pythagoras theorem

Hypotenuse² = opposite side² + adjacent side²

Therefore

z² = x² + y²

To determine the rate at which the distances are changing, we would differentiate with respect to t. It becomes

2zdz/dt = 2xdx/dt + 2ydy/dt- - - -- - -1

One travels south at 32 mi/h and the other travels east at 60 mi/h. It means that

dx/dt = 32

dy/dt = 60

Distance = speed × time

Since t = 0.5 hour, then

x = 32 × 0.5 = 16 miles

y = 60 × 0.5 = 30 miles

z² = 16² + 30² = 256 + 900

z = √1156

z = 34 miles

Substituting these values into equation 1, it becomes

2 × 34 × dz/dt = (2 × 16 × 32) + 2 × 30 × 60

68dz/dt = 1024 + 3600

68dz/dt = 4624

dz/dt = 4624/68

dz/dt = 68 mph

6 0
3 years ago
Find the volume<br> Pls don’t answer if you don’t know the correct answer.
natulia [17]

can i just get a thank you ? lol

3 0
3 years ago
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