Answer:
Step-by-step explanation:
Since we are not given the value of P, |Q|, R and S, we can as well assume values for them for the sake of this question.
Let P = 5, |Q| = 6, R =7 |S| = 2
Note that since Q and S are in modulus sign, they can return both positive and negative values.
P+Q = 5 + 6 (note that the positive value of Q is used since we need the greatest value of P+Q)
P+Q = 11
Hence the greatest value of P+Q is 11
For the least value of P+Q, we will use the negative value of Q as shown
P+Q = 5+(-6)
P+Q = 5-6
P+Q = -1
Hence the least value of P+Q is -1
Similarly:
R+S = 7 + 2 (note that the positive value of S is used since we need the greatest value of R+S)
R+S = 9
Hence the greatest value of R+S is 9
For the least value of R+S, we will use the negative value of S as shown
R+S = 5+(-2)
R+S = 5-3
R+S = 2
Hence the least value of P+Q is 2
NOTE THAT THIS ARE ASSUMED VALUES. ALL YOU NEED IS TO PLUG IN THE VALUES OF P, Q and R THAT YOU HAVE IN CASE THE VALUES DIFFERS.