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3 years ago

Write the equation of a circle that has a center at the origin and a radius with a length of 4 inches

Mathematics

2 answers:

joja [24]3 years ago

7 0

Answer:

(x)^2 + (y)^2 = 4^2

Step-by-step explanation:

The standard form of an equation for a circle is

(x-h)^2 + (y-k)^2 = r^2

where (h,k) is the center and r is the radius

Since the center is 0,0 and the radius is 4

(x)^2 + (y)^2 = 4^2

VMariaS [17]3 years ago

4 0

Answer:

x^2+y^2=16

Step-by-step explanation:

x^2+y^2=r^2 is the mother function of the equation of a circle centered at r with radius r

since r is defined to be 4 and 4^2 is 16 therefore, the equation would then be

x^2+y^2=16

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2 years ago

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krok68 [10]

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3 years ago

A solid rectangular box with height 5 m and square base with side lengths 4 m is built using a lightweight material whose densit

elena55 [62]

Answer:

627200LJ

Step-by-step explanation:

Height of box=5 m

Side of square base=4 m

Volume of rectangular box= $l\times b\times h$

Using the formula

Volume of rectangular box= $4\times 4\times 5=80m^3$

Density of material= $800kg/m^3$

We know that

$Mass=Density\times volume$

Using the formula

Mass of rectangular box= $80\times 800=64000 kg$

Gravity= $g=9.8m/s^2$

Weight of rectangular box,F= $mg=64000\times 9.8 N$

Let L be the vertical distance traveled by box

Total work done = $W=F\times displacement$

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3 years ago

Solve the system by substitution.

tino4ka555 [31]

As we know y=3/4x-3
Let's put it in the second equation
3/4x-3=1/4x+1
3/4 x -1/4 x = 1+3
2/4 x = 4
X= 4*4/2
x=8
Put x= 8 in first equation
y= 3/4 *8 -3
y=6-3
y=3
Check the answer
3=3/4 *8 -3
3=6-3
3=3
Correct
So(y, x) = (3,8)
Because x=8 and y=3

3 0

3 years ago