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Irina18 [472]
3 years ago
11

Write the equation of a circle that has a center at the origin and a radius with a length of 4 inches

Mathematics
2 answers:
joja [24]3 years ago
7 0

Answer:

(x)^2 + (y)^2 = 4^2

Step-by-step explanation:

The standard form of an equation  for a circle is

(x-h)^2 + (y-k)^2 = r^2

where (h,k) is the center and r is the radius

Since the center is 0,0  and the radius is 4

(x)^2 + (y)^2 = 4^2

VMariaS [17]3 years ago
4 0

Answer:

x^2+y^2=16

Step-by-step explanation:

x^2+y^2=r^2 is the mother function of the equation of a circle centered at r with radius r

since r is defined to be 4 and 4^2 is 16 therefore, the equation would then be

x^2+y^2=16

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Figure ABCD is a trapezoid. Find
Rudiy27

Answer:

x = 3

Step-by-step explanation:

The midsegment is half the sum of the parallel bases, that is

\frac{1}{2} (3x + 3 + 4x + 2) = 13

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3 0
3 years ago
yul has lunch at a restaurant if his bill is $14.50 and yul want to leave 20% tip what is the amount he should leave for a tip
Mariulka [41]
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3 0
3 years ago
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Please Help!!!!
Iteru [2.4K]

Step-by-step explanation:

Given : m∥n , ∠1= 50° , ∠2= 48° , and line s bisects ∠ABC

To prove = ∠3= 49°

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In figure, m∥n cut by traversal t.

So,  ∠DEF = ∠ABC(alternative exterior angles)

∠1 + ∠2 = ∠4 + ∠5

∠ABC = ∠1 + ∠2 = 50° + 48° = 98°

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∠4 = ∠5

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5 0
3 years ago
A pole-vaulter uses a 15-foot-long pile. She grips the pole so that the segment below her left hand is twice the length of the s
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Let x + 1.5 be length of segment above left hand
Let 2x be length of segment below left hand

15 = x + 1.5 + 2x
15 = 3x + 1.5
15 - 1.5 = 3x
13.5 = 3x
13.5/3= 3x/3 
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x = 4.5
This is the length above the left hand. 

2x must be then 4.5*2 = 9 foot
This is the length below the left hand. 

Checking
4.5 + 9 + 1.5 = 15 foot 

Adding length below left hand & length of left hand to right hand:
9 + 1.5 = 10.5
The right hand is hence 10.5 foot far up the pole.
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3 years ago
What is the gcf to 36 k and 144km
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