It takes 59 earth days to rotate and 88 earth days to fully orbit the sun
The asymptotes of the reciprocal function are x = 3 and y = 4. Also, the domain is x < 3 or x > 3 and the range is y < 4 or y > 4
<h3>How to determine the values of a, c, d and k?</h3>
The function is given as:
f(x) = -2[1/0.5(x -3)] + 4
A reciprocal function is generally represented as:
f(x) = a[1/(x -c)] + k
So, we have:
a = -2
c = -3 * 0.5
c = -1.5
k = 4
d = 0
Hence, the values of a, c, d and k are -2, -1.5, 0 and 4
<h3>The asymptotes</h3>
We have:
f(x) = -2[1/0.5(x -3)] + 4
Set the radical to 0
y = 0 + 4
Evaluate
y = 4
Set the denominator to 0
x - 3 = 0
Evaluate
x = 3
Hence, the asymptotes are x = 3 and y = 4
<h3>The graph of the function</h3>
See attachment for the graph of the function f(x) = -2[1/0.5(x -3)] + 4
The table of values is
x y
-4 4.6
-2 4.8
2 8
4 0
From the graph of the function, the domain is x < 3 or x > 3 and the range is y < 4 or y > 4
Read more about functions at:
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Answer:

Step-by-step explanation:
<u>Given </u><u>:</u><u>-</u><u> </u>
- Two points (-2,11) and (5,6) .
And we need to find out the slope of the equation between the two points. The slope of the line passing through two points , is given by ,
- Here the two points are (-2,11) and (5,6) .So put on the respective values ,
<u>Hence</u><u> the</u><u> </u><u>slope</u><u> of</u><u> the</u><u> line</u><u> is</u><u> </u><u>-</u><u>5</u><u>/</u><u>7</u><u> </u><u>.</u>
Answer:
9
Step-by-step explanation:
They both have -10 so just compare 3 and 12. Thats a difference of 9.
Answer: cost of 1 pot of ivy = $12
Cost of 1 rose bush =$ 10
Step-by-step explanation:
Step 1
Let rose bushes be represented as r
and pot of ivy be represented as p
such that Amy who spent 82 dollars on 7 rose bushes and 1 pot of ivy can be expressed as
7 r + p = 82----- eqn 1
Rob who spent 74 on 5 rose bushes and 2 pots of ivy can be expressed as
5r +2 p = 74----- eqn 2
Step 2
Solving
7 r + p = 82----- eqn 1
5r +2 p = 74----- eqn 2
By elimination method Multiply eqn 1 by 5 and eqn 2 by 7
35r+ 5p= 410--- eqn 3
35r+ 14p =518--- eqn 4
Subtracting eqn 4 from eqn 3
9p = 108
p = 108/9
p=12
p = pot of ivy = $12
therefore rose bush wll be ( from equation 1)
7r+ p= 82
7r=82-12
7r= 70 r= 70/7
r= rose bush =$ 10