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3 years ago

Find the surface area of the rectangle prism. 3cm 9cm and 6cm

Mathematics

1 answer:

lisabon 2012 [21]3 years ago

6 0

Answer:

198 cm²

Step-by-step explanation:

We are given the dimensions of a rectangular prism;

3cm 9cm and 6cm

We are required to determine its surface area;

We need to know that;

Surface area of a rectangular prism is given by;

A = 2(WL+HL+WH)

Where L, W and H are length , width and height respectively;

Assuming;

Width is 3 cm

Length is 9 cm, and

Height is 6 cm

Then;

Area = 2 ( (3×9) + (6×9) + (3×6))

= 2(99)

= 198 cm²

Therefore, the area of the rectangular prism is 198 cm²

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Find ST if S(-3, 10) and T(-2, 3)

FrozenT [24]

We have the following points and their coordinates:

$\begin{gathered} S(-3,10), \\ T(-2,3). \end{gathered}$

We must compute the distance ST between them.

The distance ST between the two points is given by:

$ST=\sqrt[]{(x_S-x_T)^2+(y_S-y_T)^2_{}},$

where (xS,yS) are the coordinates of the point S and (xT,yT) are the coordinates of the point T.

Replacing the coordinates of the points in the formula above, we find that:

$\begin{gathered} ST=\sqrt[]{(-3_{}-(-2)_{})^2+(10_{}-3_{})^2_{}}, \\ ST=\sqrt[]{1^2+7^2}, \\ ST=\sqrt[]{50}\text{.} \end{gathered}$

Answer: ST = √50

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1 year ago

Find the equation of the line, given the following information:

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Answer: y = 2x-2

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Step-by-step explanation:

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3 years ago

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Ksju [112]

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3 years ago

A machine at a bottling company fills water bottles. the number of bottles filled is proportional to the amount of time the mach

Whitepunk [10]

In the table shown below:

Let N be the number of bottles filled,

Let T be the time in hours.

Given that the number of bottles filled is proportional to the amount of time the machine runs, we have

$\begin{gathered} N\propto T \\ \text{Introducing a proportionality constant, we have } \\ N\text{ = kT} \\ \Rightarrow k\text{ = }\frac{N}{T} \\ \end{gathered}$

Let's evaluate the value of k for each day.

Thus, on monday,

$\begin{gathered} N\text{ = 9900} \\ T\text{ = 5.5} \\ \text{thus,} \\ k\text{ = }\frac{9900}{5.5} \\ \Rightarrow k\text{ = 1800} \end{gathered}$

Tuesday:

$\begin{gathered} N\text{ = }11160 \\ T\text{ = }6.2 \\ \text{thus,} \\ k\text{ = }\frac{11160}{6.2} \\ \Rightarrow k\text{ = 1800} \end{gathered}$

Wednesday:

$\begin{gathered} N\text{ = }12330 \\ T\text{ = }6.25 \\ \text{thus,} \\ k\text{ = }\frac{12330}{6.25} \\ \Rightarrow k\text{ = 1972.8} \end{gathered}$

Thursday:

$\begin{gathered} N\text{ = }10440 \\ T\text{ = }5.80 \\ \text{thus,} \\ k\text{ = }\frac{10440}{5.8} \\ \Rightarrow k=1800 \end{gathered}$

It is observed that all exept wednesday have the same value of k.

Thus, the amount of time required for the number of bottles filled on wednesday is evaluated as

$\begin{gathered} N\text{ = }12330 \\ k\text{ = 1800} \\ T\text{ = ?} \\ \text{but} \\ k\text{ = }\frac{N}{T} \\ 1800\text{ = }\frac{12330}{T} \\ \Rightarrow T\text{ = }\frac{\text{12330}}{1800} \\ T\text{ = 6.85} \end{gathered}$

Hence, the incorrect day is Wednesday. The amount of time for that many bottles should be 6.85 hours.

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kherson [118]

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3 years ago

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