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galben [10]
3 years ago
12

Find the surface area of the rectangle prism. 3cm 9cm and 6cm

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
6 0

Answer:

198 cm²

Step-by-step explanation:

We are given the dimensions of a rectangular prism;

3cm 9cm and 6cm

We are required to determine its surface area;

We need to know that;

Surface area of a rectangular prism is given by;

A = 2(WL+HL+WH)

Where L, W and H are length , width and height respectively;

Assuming;

Width is 3 cm

Length is 9 cm, and

Height is 6 cm

Then;

Area = 2 ( (3×9) + (6×9) + (3×6))

        = 2(99)

       = 198 cm²

Therefore, the area of the rectangular prism is 198 cm²

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One supplementary angle is 15 degrees less than twice the other. Find the measure of the two supplementary angles.
o-na [289]

Hey there!

To find our answer, we need to set up a <u><em>system of equations. </em></u>Remember, <u><em>supplementary angles</em></u> equal 180 degrees when combined. We will call one of our angles A and the other one B. Let's set it up below! :)

A=2B-15 (one angle is 15 degrees less than twice the other)

A+B=180

We need to find one of our variables. To do this, we only put one variable in the equation. But how, there are two variables in both equations! Well, as you can see, we see the A is equal to 2B-15, so we can take 2B-15 and put it into the second equation in place of A because it is equal to A, and then we will only have Bs and we can solve for it. This method is known as solving systems of equations with <u><em>substitution.</em></u>

Let's solve with substitution!

2B-15+B=180

3B-15=180              We combine our Bs.

3B=195              We add 15 to both sides.

B= 65                We divide both sides by three.

Now, we need to find what A is, but this will be really easy to do! If you remember, our angles are supplementary, so when you combine them, we will get 180, as you can see in our second equation in our first system of equations. So, we simply subtract 65 from 180.

180-65=115

Our two angles are 65° and 115°.

We can also check this with the original problem.

If you double 65, we have 130. Then, if we subtract 15, we have 115. Systems of equations are a pretty awesome way to figure this out!

I hope this helps! Have a great day!

5 0
2 years ago
Ms.Waddell put a 12-inch tall bucket under a leak in her sink. The bucket fills at a constant rate of 1/2 inch in every 1/6 of a
Angelina_Jolie [31]

Answer:

4 hours

Step-by-step explanation:

To solve this question you will simply make a ratio type equation. You know that every 1/6 of an hour, or every 10 minutes, the bucket will fill 1/2 an inch. The bucket is 12 inches tall.

\frac{10 min}{1/2 inch} = \frac{x min}{12 inches}

Cross multiply

120=\frac{1}{2} x

x=240 min

Convert minutes to inches

\frac{240 min}{1}  * \frac{1 hr}{60 min} = 4 hr

Final answer: 4 hours

Hope this helps!

8 0
3 years ago
How to do the problem ​
charle [14.2K]

Answer:

the answer is 10n-13

Step-by-step explanation:

this is a one step problem, all you need to do is add all the like terms together such as n and 9n and since they are both positives they add up to 10n and then with -10 and -3 they would add together to make -13. thats all there is to it, the answer is 10n-13

7 0
2 years ago
Read 2 more answers
a cube measuring 1 cm on each side, what is the volume, if the cube was dropped into 28ml of water. what would the new volume be
meriva

Answer:

29 ml

Step-by-step explanation:

Vcube = 1cm×1cm×1cm = 1 cm³

1 cm³ = 1 ml

If this cube is dropped into a 28ml of water the new reading will be 29 ml.

hope this helped :)

5 0
3 years ago
2 PONS
Margaret [11]

<em>The</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>of</em><em> </em><em>option</em><em> </em><em>A</em><em>.</em>

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>y</em><em>o</em><em>u</em><em>.</em><em>.</em><em>.</em>

8 0
3 years ago
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